To find the area of a trapezoid, you need the lengths of the two parallel sides (bases) and the height. However, with the provided dimensions of 3.4 inches and 5.6 inches, it's unclear which dimensions represent the bases and which represent the height. If we assume 3.4 inches and 5.6 inches are the lengths of the bases and the height is given or can be derived, the area can be calculated using the formula: Area = 0.5 × (Base1 + Base2) × Height. Without the height, we cannot calculate the area accurately.
34 multiplied by 56 is 1,904.
56 - 34 = 22
34 x 56 = 1904
34 / 56 = 0.607 0.607 x 100 = 60.7%
The area ( A ) of a trapezoid can be calculated using the formula: [ A = \frac{1}{2} \times (b_1 + b_2) \times h ] where ( b_1 ) and ( b_2 ) are the lengths of the two bases, and ( h ) is the height (altitude). Substituting the given values, ( b_1 = 3 ) in, ( b_2 = 11 ) in, and ( h = 8 ) in: [ A = \frac{1}{2} \times (3 + 11) \times 8 = \frac{1}{2} \times 14 \times 8 = 56 \text{ square inches.} ] Thus, the area of the trapezoid is 56 square inches.
A 56-inch diameter circle has an area of about 17.06 square feet.
34 multiplied by 56 is 1,904.
90
34 - 56 = -22
LCM of 34 and 56 = 952
56 - 34 = 22
34 x 56 = 1904
Factors of 56: 1 2 4 7 8 14 28 56 Factors of 34: 1 2 17 34 The GCF of 56 and 34 is 2
90 - 56 = 34 34 degrees
34 / 56 = 0.607 0.607 x 100 = 60.7%
The area ( A ) of a trapezoid can be calculated using the formula: [ A = \frac{1}{2} \times (b_1 + b_2) \times h ] where ( b_1 ) and ( b_2 ) are the lengths of the two bases, and ( h ) is the height (altitude). Substituting the given values, ( b_1 = 3 ) in, ( b_2 = 11 ) in, and ( h = 8 ) in: [ A = \frac{1}{2} \times (3 + 11) \times 8 = \frac{1}{2} \times 14 \times 8 = 56 \text{ square inches.} ] Thus, the area of the trapezoid is 56 square inches.
56 + 34 = 90 is an integer, not a fraction.