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When the shorter leg of a 30-60-90 triangle has a length of 18 what is the hypotenuse?
hypotenuse = 18/cos60 = 36
Right triangle with a hypotenuse of 18 and a leg of 6?
and the question is?
What are the two lengths of the legs of a right angle triangle with a hypotenuse of 4.2 with total area of 18?
Not enough information has been given to solve this problem.
A 45 45 90 Triangle has a hypotenuse of length 18 units What is the length of one of the legs?
12.728 (rounded)
What is the area of a right angle triangle when its perimeter is 18 cm?
It can have any area greater than 0 cm2 and less than or equal to 81(3-√8) ≈ 13.897 cm2. Without further information that provides the length of (at least) one side it is impossible to say which of these areas the triangle has. For example: base = 9 cm, hypotenuse = 9 cm ⇒ height = 18 - 9 - 9 cm = 0 cm ⇒ area = 9x0/2 = 0 cm2 This triangle does not actually exist and represents the minimum of the area. base = 6 cm, hypotenuse = 7.5 cm ⇒ height = 18 - 6 - 7.5 cm = 4.5 cm ⇒ area = 6x4.5/2 = 12.5 cm2 Note that base2 + height2 = 36 + 20.25 = 56.25 = 7.52 = hypotenuse2 and so this is a right angle triangle. base = 9(2-√2) cm ≈ 5.272 cm, hypotenuse = 18(√2 -1) cm ≈ 7.456 cm ⇒ height = 18 - 9(2-√2) - 18(√2 -1) cm = 9(2-√2) cm ≈ 5.272 cm ⇒ area = 9(2-√2) x 9(2-√2)/2 = 81(3-√8) cm2 ≈ 13.897 cm2 This triangle is a right angle triangle (check out Pythagoras on the lengths) and is the right angle triangle of largest area with perimeter 18 cm.
When the shorter leg of a 30-60-90 triangle has a length of 18 what is the hypotenuse?
hypotenuse = 18/cos60 = 36
Right triangle with a hypotenuse of 18 and a leg of 6?
and the question is?
What is the hypotenuse of a triangle 18 in x 18 in?
To find the hypotenuse of a right triangle, we can use the Pythagorean theorem, which states that the square of the hypotenuse is equal to the sum of the squares of the other two sides. In this case, both legs of the triangle are 18 inches long. So, using the formula c^2 = a^2 + b^2, where c represents the hypotenuse and a and b are the other two sides, we get c^2 = 18^2 + 18^2. Solving this equation gives us c^2 = 648, and taking the square root of 648 gives us c ≈ 25.46 inches. Therefore, the hypotenuse of a triangle with legs of 18 inches each is approximately 25.46 inches.
What are the two lengths of the legs of a right angle triangle with a hypotenuse of 4.2 with total area of 18?
Not enough information has been given to solve this problem.
If 45- 45- 90 triangle has a hypotenuse of length 18 units What is the length of one of the legs?
If a 45- 45- 90 triangle has a hypotenuse of length 18 units, the length of both of the other legs is: 12.73 units.
What is the missing length of an right triangle with length s of 7in and 18in?
If the 7" and 18" are the two legs, then the hypotenuse is 19.313" (rounded). If the 18" is the hypotenuse, then the missing leg is 16.583" (rounded).
What is the length of the hypotenuse of a right triangle with legs of 12 and 18?
Use Pythagoras' theorem: 182+122 = 468 and the square root of this is the hypotenuse which is about 21.63330765 units in length
The shorter leg of a 30 and deg-60 and deg-90 and deg triangle is 18. What is the length of the hypotenuse?
Using trigonometry and Pythagoras' theorem the length of the hypotenuse is 36
What is the length of in the right triangle below with legs of 18 and 80?
Using Pythagoras' theorem for a right angle triangle its hypotenuse is 82 units in length
A 45 45 90 Triangle has a hypotenuse of length 18 units What is the length of one of the legs?
12.728 (rounded)
What is the area of a right angle triangle when its perimeter is 18 cm?
It can have any area greater than 0 cm2 and less than or equal to 81(3-√8) ≈ 13.897 cm2. Without further information that provides the length of (at least) one side it is impossible to say which of these areas the triangle has. For example: base = 9 cm, hypotenuse = 9 cm ⇒ height = 18 - 9 - 9 cm = 0 cm ⇒ area = 9x0/2 = 0 cm2 This triangle does not actually exist and represents the minimum of the area. base = 6 cm, hypotenuse = 7.5 cm ⇒ height = 18 - 6 - 7.5 cm = 4.5 cm ⇒ area = 6x4.5/2 = 12.5 cm2 Note that base2 + height2 = 36 + 20.25 = 56.25 = 7.52 = hypotenuse2 and so this is a right angle triangle. base = 9(2-√2) cm ≈ 5.272 cm, hypotenuse = 18(√2 -1) cm ≈ 7.456 cm ⇒ height = 18 - 9(2-√2) - 18(√2 -1) cm = 9(2-√2) cm ≈ 5.272 cm ⇒ area = 9(2-√2) x 9(2-√2)/2 = 81(3-√8) cm2 ≈ 13.897 cm2 This triangle is a right angle triangle (check out Pythagoras on the lengths) and is the right angle triangle of largest area with perimeter 18 cm.
The sides of a right triangle are 18 inches and 24 inches in length how long would the hypotenuse of this triangle be?
H = sqrt (324 + 576) = sqrt 900 = 30 in
