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When the shorter leg of a 30-60-90 triangle has a length of 18 what is the hypotenuse?
hypotenuse = 18/cos60 = 36
Right triangle with a hypotenuse of 18 and a leg of 6?
and the question is?
What are the two lengths of the legs of a right angle triangle with a hypotenuse of 4.2 with total area of 18?
Not enough information has been given to solve this problem.
A 45 45 90 Triangle has a hypotenuse of length 18 units What is the length of one of the legs?
12.728 (rounded)
What is the area of a right angle triangle when its perimeter is 18 cm?
It can have any area greater than 0 cm2 and less than or equal to 81(3-√8) ≈ 13.897 cm2. Without further information that provides the length of (at least) one side it is impossible to say which of these areas the triangle has. For example: base = 9 cm, hypotenuse = 9 cm ⇒ height = 18 - 9 - 9 cm = 0 cm ⇒ area = 9x0/2 = 0 cm2 This triangle does not actually exist and represents the minimum of the area. base = 6 cm, hypotenuse = 7.5 cm ⇒ height = 18 - 6 - 7.5 cm = 4.5 cm ⇒ area = 6x4.5/2 = 12.5 cm2 Note that base2 + height2 = 36 + 20.25 = 56.25 = 7.52 = hypotenuse2 and so this is a right angle triangle. base = 9(2-√2) cm ≈ 5.272 cm, hypotenuse = 18(√2 -1) cm ≈ 7.456 cm ⇒ height = 18 - 9(2-√2) - 18(√2 -1) cm = 9(2-√2) cm ≈ 5.272 cm ⇒ area = 9(2-√2) x 9(2-√2)/2 = 81(3-√8) cm2 ≈ 13.897 cm2 This triangle is a right angle triangle (check out Pythagoras on the lengths) and is the right angle triangle of largest area with perimeter 18 cm.
