Assuming that the table is rectangular, the perimeter is 16 feet; 5 + 5 + 3 + 3
Gg
12 squft
5 feet
Find the area of a rectangle that is 3 feet wide and 5 feet long.
9 feet x 5 feet = 45 sq. feet
Assuming that the table is rectangular, the perimeter is 16 feet; 5 + 5 + 3 + 3
15 square feet
Gg
12 squft
Approximately 127.84 square feet.
In a rectangular figure, square feet a generated when you multiply the length of an area by its width. So if a rectangle is 3 feet long by 5 feet wide, the area is 3 x 5 = 15 square feet. If you are dealing with a triangle, the area is half the length by the height... so a triangle 3 feet wise at the base, and 5 feet high, would be 0.5 x (3 x 5) = 0.5 x 15 = 7.5 square feet. If you are dealing with circles, the area is derived from the radius. If the radius is 3 feet, the formula is pi x r2 .... in this case pi x 32 or 9 x pi. Taking pi as 3.14 we get an area of 28.27 sq feet.
5 feet
Impossible to answer ! A room 5 feet by 15 feet will have the same area as one that's 3 feet by 25 feet !
135 square feet.
it is 15 ft
Find the area of a rectangle that is 3 feet wide and 5 feet long.