Diameter = 32 inches, hence radius = 16 inches Area of circle = pi x r x r = 3.1415 x 16 x 16 = 804.224 square inches
Diameter = 32 inches so radius = 16 inches. Then area = pi*r2 = 804 sq inches (to the nearest integer).
The area of a circle is pi * r2. The area is 32, so 32 = pi * r2 32/pi = r2 r = sqrt(32/pi) d = 2 * sqrt(32/pi) d = 6.38307649 inches
The area of a circle if the diameter is 32 feet is: 804.2 square feet.
32 inches of course.
Diameter = 32 inches, hence radius = 16 inches Area of circle = pi x r x r = 3.1415 x 16 x 16 = 804.224 square inches
Diameter = 32 inches so radius = 16 inches. Then area = pi*r2 = 804 sq inches (to the nearest integer).
256*pi square inches Area of a circle = pi*radius2
A circle with a radius of 16 inches (32/2) has a circumference of 100.53 inches.
The area of a circle is pi * r2. The area is 32, so 32 = pi * r2 32/pi = r2 r = sqrt(32/pi) d = 2 * sqrt(32/pi) d = 6.38307649 inches
The area of a circle if the diameter is 32 feet is: 804.2 square feet.
A circle with a radius of 32 inches has an area of 3,216.99 square inches.
32 inches of course.
32"
It is 64 inches.
circumference = π x diameter ⇒ diameter = circumference ÷ π = 32 in ÷ π ≈ 10.19 in
A 32-inch circle has an area of 804 square inches.