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How can you construct a perpendicular bisector of a given segment using only two parallel edges of a straightedge with out usign any mesurements on the ruler and compass?
Do I have a compass to use or not ? It's not clear from your question, but since you mentioned it at the end of the question, I'll assume that I do have a compass, and in that case, I only need one straight-edge. 1). Plant the compass on one end of the line segment, open it to more than half the length of the segment, draw a long arc that crosses the segment. 2). Keep the same opening, pick up the compass. 3). Plant the compass on the other end of the segment, draw another long arc that crosses the segment. 4). Sell the compass. 5). The two arcs intersect at two points on opposite sides of the segment. With your straight edge, draw a line between these two points. That line is the perpendicular bisector of the original segment.
Can you draw an equilateral triangle using a straightedge and compass?
Yes, it is quite simple.Draw a straight line segment, AB. Put the compass point at A and open it so that the pencil point is at B. Then draw an arc. Next, without changing the compass setting move it to B and draw another arc to cut the previous arc at C. [Actually there will be two points, one on either side of AB.] Using the straight edge, join AC and BC. Then ABC is an equilateral triangle.
How do you know whether to use a open circle or a closed circle?
If points on the circumference are excluded from the locus then an open circle, else a closed one.
How do you know whether to use an open circle or a closed circle when graphing an inequality?
If the inequality is > or< then it is an open circle. If it is greater than or equal to or less than or equal to, it is a closed circle.
Open circle at -5 open circle at 4 and shaded between -5 and 4?
Yes, and the question is ... ?
