Hmmm. the triangle you describe is HALF of a rectangle...
It is: perimeter minus hypotenus+base = height Area = 0.5*base*height
area of any triangle = (1/2)*base*height . you can consider the hypotenuse as the base and the leg as the height . (1/2)(68)(60) (68)(30) 2040 square millimeters
A right triangle with a hypotenuse of 10m and a base of 5m has an area of: 21.65m2
Providing that it is a right angle triangle its area is about 73 square inches. Solved by using Pythagoras and 1/2*base*height = area
if you know the two legs of the triangle, you can use the Pythagorean theorem to find the hypotenuse as the base. Then you use the formula to find the area of the triangle: 1/2 (pi) bh.
The area of triangle is : 127.5
The area of a right triangle with base of 8 and height of 8 is: 32 square units. The hypotenuse is 11.31 units.
Area = 0.5*base*height You will need to know the base or height then use Pythagoras theorem to find the base or height.
It is: perimeter minus hypotenus+base = height Area = 0.5*base*height
area of any triangle = (1/2)*base*height . you can consider the hypotenuse as the base and the leg as the height . (1/2)(68)(60) (68)(30) 2040 square millimeters
The hypotenuse alone does not provide enough information to determine the area of a triangle.
The length of the hypotenuse, alone, is not sufficient to determine the area of a triangle.
A right triangle with a hypotenuse of 10m and a base of 5m has an area of: 21.65m2
26
Providing that it is a right angle triangle its area is about 73 square inches. Solved by using Pythagoras and 1/2*base*height = area
if you know the two legs of the triangle, you can use the Pythagorean theorem to find the hypotenuse as the base. Then you use the formula to find the area of the triangle: 1/2 (pi) bh.
The area of triangle is : 44.0