Hmmm. the triangle you describe is HALF of a rectangle...
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It is: perimeter minus hypotenus+base = height Area = 0.5*base*height
area of any triangle = (1/2)*base*height . you can consider the hypotenuse as the base and the leg as the height . (1/2)(68)(60) (68)(30) 2040 square millimeters
A right triangle with a hypotenuse of 10m and a base of 5m has an area of: 21.65m2
Providing that it is a right angle triangle its area is about 73 square inches. Solved by using Pythagoras and 1/2*base*height = area
if you know the two legs of the triangle, you can use the Pythagorean theorem to find the hypotenuse as the base. Then you use the formula to find the area of the triangle: 1/2 (pi) bh.