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20.535 cm2

Let one leg be x cm, then the other is (x + 1.85) cm, and using Pythagoras:

x2 + (x + 1.85)2 = 9.252

→ x2 + x2 + 3.7x + 3.4225 = 85.5625

→ 2x2 + 3.7x - 82.14 = 0

→ x = (-3.7 ± √(3.72 - 4 x 2 x -82.14)) / (2 x 2)

= (-3.7 ± 25.9) / 4

= 5.55 or -7.4

The negative value can be ignored as the length of a side must be greater than zero.

Thus, the triangle has sides 5.55 cm, 5.55 + 1.85 = 7.4 cm and 9.25 cm, and its area is:

area = 1/2 x 7.4 cm x 5.55 cm

= 20.535 cm2

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Q: What is the area of a right angle triangle whose hypotenuse is 9.25 cm and has one leg longer than the other by 1.85 cm?
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