Area = 0.5*5*12 = 30 square units
Yes.
Two sides of a triangle are not enough to determine its shape and so it is impossible to find its area.
About 62 Feet squared
With sides of 5 and 12, you can make a triangle with any perimeter you want between 24 and 34. If you call them "legs" because they are the sides of a right triangle, then the hypotenuse is 13, and the perimeter is 30.
It's a right angle triangle and its length is 12 units of measurement.
Yes.
(12*12)/2 = 72
Two sides of a triangle are not enough to determine its shape and so it is impossible to find its area.
False. It can't be.In a right triangle, the sum of the squares of the two short sides is equal to the squareof the longest side.122 = 144152 = 225-------------sum = 369202 = 400, not 369.So these are not the sides of a right triangle.
What is 12 in ? And what is 16 in ? ? Are they the lengths of two sides of the triangle ? Are they the length of one side and the height of the triangle ? The area of any triangle is 1/2 of the product of (length of its base) x (its height).
About 62 Feet squared
The answer depends on the labels of the sides which are 19 and 12.
If you divide the equilateral triangle into two right angle triangles then the hypotenuse will be 12 feet.
12
With sides of 5 and 12, you can make a triangle with any perimeter you want between 24 and 34. If you call them "legs" because they are the sides of a right triangle, then the hypotenuse is 13, and the perimeter is 30.
Yes they do for a triangle using Pythagorean theorem 5 squared + 12 squared = 13 squared
No. Pythagoras' theorem states that when the square of the hypotenuse is equal to the sum of the squares of the other two sides then it is a right-angled triangle. The hypotenuse is the longest side (opposite the supposed right angle). In this case the hypotenuse is 20. The square of 20 is 400. The other two sides are 12 and 15. The square of 12 is 144 and the square of 15 is 225. The sum is therefore 225 + 144 = 369, which is not equal to 400, therefore the triangle cannot be a right-angled triangle.