Area of 3/5 of a circle: 3/5*pi*15^2 = 135*pi square feet
center (3,0) radius 12 So the equation is (x-3)^2 + y^2 = 144 → y^2 + x^2 - 6x - 135 = 0 in general a circle of radius r centered at (h, k) has the equation: (x - h)^2 + (y - k)^2 = r^2
A 1/4 of a circle is 90 degrees 1/8 of a circle is 45 degrees and they both add up to 135 degrees
3/4 equals 75%. 75% of 180 degrees is 135. .75 x 180 = 135 degrees.
You cannot. There are infinitely many possible parallelograms whose area is 135 square units, each with a different base (and so a different height).
Area of 3/5 of a circle: 3/5*pi*15^2 = 135*pi square feet
3.82 units
The circumference of a circle it Pi times the diameter. The diameter is 2 times the radius. So the diameter is 135 and Pi is 3.1416. So the circumference is 424.115 metres.
If you mean a circle of diameter 135 feet, the area is Pi x 1352/4 = 14315.7 sq ft
135 feet!
center (3,0) radius 12 So the equation is (x-3)^2 + y^2 = 144 → y^2 + x^2 - 6x - 135 = 0 in general a circle of radius r centered at (h, k) has the equation: (x - h)^2 + (y - k)^2 = r^2
The atomic radius of nickel is about 135 picometers (pm).
The atomic radius of germanium (Ge) is about 122 picometers (pm).
135 degrees.
To find the diameter of a circle with a circumference of 135 cm, you can use the formula C = πd, where C is the circumference and d is the diameter. Plugging in the given circumference of 135 cm, you get 135 = πd. To solve for d, you divide both sides by π, giving you d = 135/π ≈ 42.97 cm. Therefore, the diameter of the circle is approximately 42.97 cm.
The atomic radius of a cobalt atom is about 135 picometers (pm) or 1.35 angstroms (Å).
The atomic radius of cobalt is about 135 pm (±5 pm).