I will assume that it is a regular polygon (it isn't given if the interior angles are the same, but then the answer would not be a constant).
900 sides means 900 vertices which means 900 lines from the center and 900 congruent isosceles triangles formed by these lines. Now the polygon is 900*area of one triangle. The vertex of each isosceles triangle is 360o over 900, or 2/5o. We know the base to be 11 inches and find the height to be about 27.1 inches (using 5.5/tan(.2)). The area of one triangle is about 149.23. The area of the entire polygon is about 134305 square inches.
how do you find area of a square that has sides of length 96 inches
The answer depends on what the shape is. A quadrilateral is not a rigid shape and information about the length of its four sides is not enough to determine its shape.
Length and side: 7 inches and 5 inches respectively
A square with a side length of 3 inches has an area of 9 square inches.
The area is 64 square inches. Multiply length by width to get the area.
how do you find area of a square that has sides of length 96 inches
The answer depends on what the shape is. A quadrilateral is not a rigid shape and information about the length of its four sides is not enough to determine its shape.
By definition, an equilateral triangle has all three sides of equal length! So it is impossible for it to have sides of length 10 inches and 7 inches!
The perimeter of a shape is the total length of its boundary or the sum of the lengths of all its sides. It is measured in linear units such as inches, feet, or meters. The area of a shape is the measure of the surface enclosed by the shape's boundary. It is measured in square units such as square inches, square feet, or square meters.
To find the area of a shape with 6-inch sides, we first need to determine the type of shape. Assuming it is a square, the formula for the area of a square is side length squared. Therefore, the area would be 6 inches squared, which equals 36 square inches.
Length and side: 7 inches and 5 inches respectively
A square with a side length of 3 inches has an area of 9 square inches.
The area is 64 square inches. Multiply length by width to get the area.
Do you mean the surface area of the box? If so... What you do is break the surface area into 6 rectangles: Two rectangles have sides of length 6.3 and 12.6 inches. Two rectangles have sides of length 6.3 and 4.2 inches. Two rectangles have sides of length 12.6 and 4.2 inches. Find the area of each of the six rectangles (using the standard formula for the area of a rectangle, A = W x H), and add up all six. The sum of the areas of the six rectangles will be the surface area of the box. Since the lengths of the sides are in inches, the area will already be in square inches, and therefore you don't have to "turn it into square inches".
A square with a side length of 4.5 inches has an area of 20.25 square inches.
78 square inches per side.
Because y = ax is maximum when a = x