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What is the area of a triangle when its shortest side is less than the other sides by 18.55 cm and 21.2 cm respectively showing brief details of your work?
Presumably it's a right angle triangle so use Pythagoras' theorem and let the hypotenuse be (x+21.2) the height be (x+18.55) and the base be x:-
(x+21.2)2-(x+18.55)2 = x2
If: (x2+42.4x+449.44)-(x2+37.1x+344.1025) = x2
Then: -x2+5.3x+105.3375 = 0
Solving the above by means of the quadratic equation formula gives x a positive value of 13.25
So the dimensions are: hypotenuse 34.45 cm, height 31.8 and base 13.25 cm
Area = 0.5*31.8*13.25 = 210.675 square cm
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