By plotting the given vertices and then joining them together on the Cartesian plane the shape of a isosceles triangle will be formed with an area of 78 square units.
The vertices (-3, 7) and (2, 19) and (10, 7) will form an isosceles triangle when plotted on the Cartesian plane with angles of 67.38 degrees, 56.31 degrees and 56.31 degrees all rounded to two decimal places and the area of the triangle works out as 78 square units.
It is an isosceles triangle with a perimeter of 26+(4 times square root of 13) linear units and an area of 78 square units
The given vertices when plotted on graph paper will form an isosceles triangle with 2 equal exterior angles of 123.69 degrees and a 3rd exterior angle of 112.62 degrees with an area of 78 square units
Area = 0.5*base*height = 0.5*20*19 = 190 square in.
The area of a triangle is (base)x(height)x1/2.So, we put in your values (base=19, height=14) and we get 19x14x1/2=19x7=133.The area of a triangle with a base of 19cm and a height of 14cm is 133.
The vertices (-3, 7) and (2, 19) and (10, 7) will form an isosceles triangle when plotted on the Cartesian plane with angles of 67.38 degrees, 56.31 degrees and 56.31 degrees all rounded to two decimal places and the area of the triangle works out as 78 square units.
It is an isosceles triangle with a perimeter of 26+(4 times square root of 13) linear units and an area of 78 square units
The given vertices when plotted on graph paper will form an isosceles triangle with 2 equal exterior angles of 123.69 degrees and a 3rd exterior angle of 112.62 degrees with an area of 78 square units
The points (-3, 7) and (10, 7) lie on the same horizontal line as the y-coordinates are the same), therefore it is best to take this as the base of the triangle; it is 10 - -3 = 10 + 3 = 13 units long.The third point (2, 19) is 19 - 7 = 12 units above this line which is the height of the triangle.Thus the area is ½ × base × height = ½ × 13 units × 12 units = 78 square units.Another possible answer:-Distance formula: square root of (x2 -x1) together with +(y2 -y1)Using the distance formula for the given vertices it works out that it is an isosceles triangle with equal sides of 13, a base of 4 times square root of 13 and a height of 3 times square root of 13.Therefore area is: 0.5*4 times sq rt 13*3 times sq rt 13 = 78 square unitsChecking using Pythagoras' theorem will confirm that it is an isosceles triangle.
Area = 0.5*base*height = 0.5*20*19 = 190 square in.
American Gothic - 1995 Triangle 1-19 was released on: USA: 10 July 1996
19
19. sides=vertices
The area of a triangle is (base)x(height)x1/2.So, we put in your values (base=19, height=14) and we get 19x14x1/2=19x7=133.The area of a triangle with a base of 19cm and a height of 14cm is 133.
it has 6 faces 19 edges and 5 vertices
The area of every triangle is 1/2 the product of (length of the base) x (the height).Armed with that information, you can easily calculate the area of your triangle, andany others that you might encounter in the future. Go forth and multiply !
A decahedron is a polyhedron with 10 faces. There are several versions of a decahedron, but none of these are regular. By definition, they all have 10 faces. There is the octagonal prism - with 24 edges and 16 vertices, the square anti-prism, with 16 edges and 8 vertices, the square cupola, with 20 edges and 12 vertices, the pentagonal bi-pyramid, with 15 edges and 7 vertices and the augmented pentagonal prism, with 19 edges and 11 vertices. See, for example, http://en.wikipedia.org/wiki/Decahedron