Rectangle ABCDArea=x__Length=ABWidth= x/AB
12
Suppose the sides of the rectangle ABCD are not parallel to the axis. Then if A = (p,q) and B = (r, s) then by Pythagoras, |AB|2 = (p - r)2 + (q - s)2 from which AB can be calculated. Calculate BC in a similar fashion and then area = AB*BC If AB is parallel to an axis (say the x axis), then q = s so that q - s = 0 and |AB|2 simplifies to (p - r)2 + 02 so that |AB| = |p - r|
Without knowing where a, b and h are, we have no way of knowing whether ab and ah are lengths, widths or diagonals and consequently, no way of determining the area.
All the trigonometric functions are derived from the right angled triangle. If we consider the three sides (AB, BC, CA) of a triangle and the included angle. There is a possibility of getting six functions based on the ratios like AB/AC, BC/AC, AB/BC, BC/AB, AC/BC, AC/AB . So we will have six trigonometric functions
Rectangle ABCDArea=x__Length=ABWidth= x/AB
12
Suppose the sides of the rectangle ABCD are not parallel to the axis. Then if A = (p,q) and B = (r, s) then by Pythagoras, |AB|2 = (p - r)2 + (q - s)2 from which AB can be calculated. Calculate BC in a similar fashion and then area = AB*BC If AB is parallel to an axis (say the x axis), then q = s so that q - s = 0 and |AB|2 simplifies to (p - r)2 + 02 so that |AB| = |p - r|
A rectangular box has six sides. Find the area of them and add them together. Two sides are length times height, two sides are length times width, and two sides are width times height. Surface Area = 2LH + 2LW + 2WH
Area of a rectangle = length of base x height Area of a triangle = (length of base x height)/2 A.............................................. B mmmmmmmmmmmmmmmmmmm m.............................................. m m ..............................................m m.............................................. m m.............................................. m m.............................................. m m ..............................................m m.............................................. m mmmmmmmmmmmmmmmmmmm C ..............................................D Area of ABCD = AB x AC Area of ABCD = (AB X AC)/2 Then Area of ABCD = 2 Area of ABC
You need to prove that there are two pairs of sides with equal lengths. Imagine a rectangle A C B D Since side AB is equal in length to side CD that is one equal pair. Likewise, AC is equal to BD and is the other equal pair. Since there are two equal parallel pairs, the angles must all be 90 degrees by rules of geometry so it is a rectangle. Note: The same thing may be used to prove a square, except a square has all sides of the same length. ================================================ If you can prove any one of these statements, then your quadrilateral is a rectangle: -- Opposite sides are parallel and any one angle is a right angle. -- Opposite sides are equal and any one angle is a right angle. -- All four angles are right angles. -- Adjacent angles are complementary, and one of them is a right angle. -- Opposite sides are either equal or parallel, and area is equal to the product of two adjacent sides. -- Diagonals are equal.
The formula for a rectangle is height x width (A=ab)Since you said surface area, I'm pretty sure that you might mean a rectangular prism. To get this, you would need to find the area of each "rectangle side". To do this, you use the first formula, using height (a), width (b), and depth (c). The formula for theSurface Area of a Rectangular Prism = 2ab + 2bc + 2ac
With sides of length A, B and C units, the total surface area is 2*(AB + BC + CA) square units.
A rectangle has all angles equal to 90*. So you can apply the Pythagoras theorem as the diagonal, length, and width form a right angle triangle -> AB²= BC² + CB² where AB is the hypotenuse ( side opposite to 90*), and BC and CD are the other two sides. So in your case 18.9²= Lenght² + 6.7². Length= √18.9²-6.7²= √357.21-44.89= √312.32= 17.672577627499617 cm is your answer.
if it is a square
It need not be a complex shape. You can have a rectangle with these properties. Just solve the two equations: 2a + 2b = 100 (for the perimeter) ab = 105 (for the area)
B