The Perimeter
Each face of a cube is a square. You simply square the length of each edge to find the area of the face. In this case, 4 inches squared = 4 x 4 which gives you 16 square inches per face.
Assuming your cube is actually a cube, each plane (face) would be 36 square inches. Multiply by six for your total surface area.
Each face of the cube has 1/6 of the area = 78/6 = 13 in2 .Each side of the face = square root of the area = sqrt(13) inches .The volume of the cube is (side length)3 = [ sqrt(13) ]3 = 46.872 in3 (rounded)
If the length of each edge of the cube is 's',then the area of each face is s2.
The Perimeter
Each face of a cube is a square. You simply square the length of each edge to find the area of the face. In this case, 4 inches squared = 4 x 4 which gives you 16 square inches per face.
100 square inches
Assuming your cube is actually a cube, each plane (face) would be 36 square inches. Multiply by six for your total surface area.
If the length of the side is S, the area of the faces of the cube is 6*S^2. There are six faces to the cube, and each face is S*S. For example, if the side of the cube is 2 inches, the area of a face is 2*2 = 4 square inches. Six faces means the overall area is 6*4 = 24 square inches.
Each face of the cube would have an area of 4*4 = 16 sq inches. A cube has 6 faces so the total surface area = 6*16 = 96 sq inches.
Each face of the cube has 1/6 of the area = 78/6 = 13 in2 .Each side of the face = square root of the area = sqrt(13) inches .The volume of the cube is (side length)3 = [ sqrt(13) ]3 = 46.872 in3 (rounded)
If the length of each edge of the cube is 's',then the area of each face is s2.
Six times the area of one face...
each face of the cube as a area of length2 and there are 6 faces therefore 6(5)2 = 150 inches2
The edges are 4 inches long. Than you take how many faces and than multiply. Your answer is 16.
A cube has 6 faces. Each face will be 7.5 times 7.5 = 56.25 square inches. Therefore the surface area of the culbe will be 6 times 56.25 = 337.5 square inches.