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well, for one thing, what polygon is it. a triangle, a quadrilateral, what!? Two, if its only side is 8in., then it is not a polygon at all. it needs to be a closed plane of connecting lines.

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Q: What is the area of regular polygon with the side length of 8in.?
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What is the area of a regular polygon if the radius is 8 cm?

The area of a regular polygon with n sides is the half of the product of its perimeter and the apothem. So that you do not have enough information to find the area of the polygon (for example how many sides it has, or the side length).


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If it's a regular polygon, and you know the length of the perpendicular from the center to the middle of a side, and the length of a side, A = LNS, where L is the length of the perpendicular, N is the number of sides, and S is the number of sides. See the link for a more detailed explanation of various ways to compute the area of regular polygons.


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The length of each side is (115 inches)/(the number of sides in the polygon) .


A regular octagon with sides of length 11 and an apothem of length 8.85 has an area of what?

An apothem of a regular polygon is a segment from its center to the midpoint of a side. You can use the apothem to find the area of a regular polygon using this formula: A = pa/2 where p is the perimeter of the figure and a is the apothem. For a regular octagon with side length 11, the perimeter p = 8(11) = 88. So the area would be A = 88(8.85)/2 = 389.4 square units.


How do you find the permeter of a polygon?

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