5,5
Any number can be an arithmetic mean. SO just pick any three numbers between -2 and 12. And if you want to find a set of numbers for which your selected number is a mean add 1 and subtract 1 from it, or add 2 and subtract 2 from it (or do both). Suppose you pick 8. Add 1 and subtract 1: 7 and 9. 8 IS the arithmetic mean of 7 and 9. Add 2 and subtract 2: 6 and 10. 8 is the arithmetic mean of 6 and 10. It is also the AM of 6, 7, 9 and 10.
10. It is what you get when you add the two numbers together and divide by two and it is the number that is halfway between the two numbers.
100
To get the arithmetic mean, sum them up and divide by the count (in this case 10). So we have 12 + 14 + 15 + 16 + 18 + 20 + 21 + 22 + 24 + 25 = 187. Divide by 10 is 18.7
5,5
-9
Any number can be an arithmetic mean. SO just pick any three numbers between -2 and 12. And if you want to find a set of numbers for which your selected number is a mean add 1 and subtract 1 from it, or add 2 and subtract 2 from it (or do both). Suppose you pick 8. Add 1 and subtract 1: 7 and 9. 8 IS the arithmetic mean of 7 and 9. Add 2 and subtract 2: 6 and 10. 8 is the arithmetic mean of 6 and 10. It is also the AM of 6, 7, 9 and 10.
10 and 17
10. It is what you get when you add the two numbers together and divide by two and it is the number that is halfway between the two numbers.
100
To get the arithmetic mean, sum them up and divide by the count (in this case 10). So we have 12 + 14 + 15 + 16 + 18 + 20 + 21 + 22 + 24 + 25 = 187. Divide by 10 is 18.7
The arithmetic mean of 10, 11, and 6 is 9. Add them together then divide by 3.
The mean is 8 because: (1+6+10+11+12)/5=8 We know that the Arithmetic Mean of a data set = (sum of all the items)/ number of items. =(1+6+10+11+12)/5 =(40)/5 =8. The Arithmetic Mean of 1, 6, 10, 11, and 12 is 8.
The mean of the numbers a1, a2, a3, ..., an is equal to (a1 + a2 + a3 +... + an)/n. This number is also called the average or the arithmetic mean.The geometric mean of the positive numbers a1, a2, a3, ... an is the n-th roots of [(a1)(a2)(a3)...(an)]Given two positive numbers a and b, suppose that a< b. The arithmetic mean, m, is then equal to (1/2)(a + b), and, a, m, b is an arithmetic sequence. The geometric mean, g, is the square root of ab, and, a, g, b is a geometric sequence. For example, the arithmetic mean of 4 and 25 is 14.5 [(1/2)(4 + 25)], and arithmetic sequence is 4, 14.5, 25. The geometric mean of 4 and 25 is 10 (the square root of 100), and the geometric sequence is 4, 10, 25.It is a theorem of elementary algebra that, for any positive numbers a1, a2, a3, ..., an, the arithmetic mean is greater than or equal to the geometric mean. That is:(1/n)(a1, a2, a3, ..., an) ≥ n-th roots of [(a1)(a2)(a3)...(an)]
10 X 87 =870 So the total for George's 10 tests is 870 870 - 95 -55 = 720 So George now has 720 for 8 tests. 720 divided by 8 is 90 Therefore George's new arithmetic mean is 90
The multiples of ten from 10 to 190 inclusive are 10, 20, 30, ..., 190. The average arithmetic mean of these numbers can be calculated by adding all the numbers together and then dividing by the total count of numbers. In this case, there are 19 numbers from 10 to 190, and the average arithmetic mean is 100.