Sum/Count = 66/11 = 6
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∙ 11y ago11+9=20 20/2=10 average:10
9/10+1/5... 1/5=2/10 therefore 9/10+2/10=11/10 11/10= 1 1/10
3/5 + 1/2 = 6/10 + 5/10 = 11/10 = 11/10
sorted: 1 2 7 9 11 15 19 20 number of items: 8 middle items: 9 and 11 average of middle items, or median: (9+11)/2 = 10
-7/10 - 2/5 = -7/10 - (2×2)/(5×2) = -7/10 - 4/10 = -11/10 = -1 1/10
The average of 11, -14 and 10 is 2.33... (repeating).
2
3 1/10 = 2 11/10 2 1/5 = 2 2/10 2 11/10 - 2 2/10 = 9/10
add -10... 11 + (-10) = 11-10=1 ur welcome! So that would be 2x + 11 = 1 where x = -5.
(5/6) * (1/10) + (2/3) / (4/11) = (5/6) * (1/10) + (2/3) * (11/4)= (1/12) + (11/6) = 1/12 + 22/12 = 23/12 or 111/12(5/6) * (1/10) + (2/3) / (4/11) = (5/6) * (1/10) + (2/3) * (11/4)= (1/12) + (11/6) = 1/12 + 22/12 = 23/12 or 111/12(5/6) * (1/10) + (2/3) / (4/11) = (5/6) * (1/10) + (2/3) * (11/4)= (1/12) + (11/6) = 1/12 + 22/12 = 23/12 or 111/12(5/6) * (1/10) + (2/3) / (4/11) = (5/6) * (1/10) + (2/3) * (11/4)= (1/12) + (11/6) = 1/12 + 22/12 = 23/12 or 111/12
5d-1=-11 5d=-11 + 1 5d=-10 d= -10/5 d=-2
The factors of 6 are: 1, 2, 3, 6 The factors of 8 are: 1, 2, 4, 8 The factors of 10 are: 1, 2, 5, 10 The factors of 11 are: 1, 11 The only factor common to all of them is: 1.
Because we are counting in base 10, and the next number after 1 is 2, not 11.
11 because 4+1=5 3+5=8 2+8=10 1+10=11 0+11=11
11/10 or 1 and one tenth.1/2 + 3/5= find the same factor for the denominator (bottom) =10= 5/10 + 6/10= 11/10= 1/1/10
11 = 1*8 + 1*2 + 1*1 = 1(2)3 + 1(2)1+ 1(2)0. Thus, in binary (base 2) 11 is represented as: 1011. To double check we get: 8 + 2 + 1 = 11 (base 10).
The total T of adding numbers from 1 to n is (n x (n+1))/2; consider if n=10: adding 1+ 2+ 3+...+ 8+ 9+ 10= T and adding 10+ 9+ 8+...+ 3+ 2+ 1= T (the same answer) Now add the the two lines together---> 11+11+11+..+11+11+11= 2T, so there are 10 11s 10 x 11 =2T, divide both sides of the equal sign by 2 (10 x 11)/2 =T So, where n=10, T=55