4 + 4 = 8 8 x 4 = 32 32 + 4 = 36 36 + 3 = 39 39 + 3 = 42 42 + 3 = 45
90
90
45+73+3+7=128 then divide by 4 so answer is 32
39/45 = (3*13)/(3*15) = 13/15
The answer is A. (32+45+39)/3
4 + 4 = 8 8 x 4 = 32 32 + 4 = 36 36 + 3 = 39 39 + 3 = 42 42 + 3 = 45
The way to calculate an average is to add up all items and divide the total by the number of items. In this case, add up the prices of all 3 text books (32 + 45 + 39 = 116) then divide by 3 (books) to get 38.66, your average price. If the textbooks cost $32 and $45 and $39, then the total, found by simply adding the individual costs, is $32 + $45 + $39 = $116 total cost. The average cost of each book is the total cost divided by the number of books, and that's $116/3 = $38.66 plus 2/3rds cents per book. It might be written as 38 dollars and 66 and 2/3rds cents, or possibly $32.66666....
90
90
The average price of his books are $38.67
45+73+3+7=128 then divide by 4 so answer is 32
1, 3, 13, 39 1, 3, 5, 9, 15, 45
The GCF of 6, 39, and 45 is 3.
39/45 = (3*13)/(3*15) = 13/15
The factors of 18 are: 1, 2, 3, 6, 9, and 18.The prime factors of 18 are: 2 and 3.The factors of 39 are: 1, 3, 13, and 39.The prime factors of 39 are: 3 and 13.The factors of 45 are: 1, 3, 5, 9, 15, and 45.The prime factors of 45 are: 3 and 5.
It is: 3*3*5 = 45 or as 32*5 = 45