7.
3, 4, 5, 6, 7, 8, 9, 10, 11
Average = Sum.Count = (6+9+7+10)/4 = 32/4 = 8 cm.
16 + 2 + 9 + 4 + 7 + 8 is = 18 + 9 + 4 + 7 + 8 = 27 + 4 + 7 + 8 = 31 + 7 + 8 = 38 + 8 = 46
6333
It is (9 + 9 + 7 + 7)/4 = 8
Average = (8 + 9 + 5 + 6)/4 = 7Average = (8 + 9 + 5 + 6)/4 = 7Average = (8 + 9 + 5 + 6)/4 = 7Average = (8 + 9 + 5 + 6)/4 = 7
4+8+9= 21 divide 21 by 3 (you have three numbers) = 7
7 + 8 + 10 + 11 = 36 / 4 = 9
3, 4, 5, 6, 7, 8, 9, 10, 11
Average = Sum.Count = (6+9+7+10)/4 = 32/4 = 8 cm.
16 + 2 + 9 + 4 + 7 + 8 is = 18 + 9 + 4 + 7 + 8 = 27 + 4 + 7 + 8 = 31 + 7 + 8 = 38 + 8 = 46
Stanines of 1,2, and 3 are below average, 4, 5, and 6 are average, and 7, 8, and 9 are above average.
6333
The mean average is (9 + 15 + 4 + 8) ÷ 4 = 9; The median average is (8 + 9) ÷ 2 = 8.5 The mode average doesn't exist as each number appears once.
9+8+7 = 24, divided by 3 (the amount of numbers) = 8
The median of a set of numbers is the middle one (if there are an odd number of them) or the mean average of the middle two (if there are an even number of them). The dataset {4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 8, 9, 10, 11} has 14 elements, so the median is the mean average of the 7th and 8th numbers. The 7th and 8th numbers are 7 and 7, thus the median is (7 + 7) / 2 = 7.
8 - (9 ÷ (5 + 4)) = 7