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They are the first 2000 numbers that have only 2 factors which are themselves and one
2,001,000.
Answer is 4000000: The sum of the first N odd numbers is N^2. Look at 1,3,5 for example. There are 3 numbers and the sum is 9 which is 3^2. Add 7 and the sum is 16 which is 4^2. So the of the first 2000 consecutive odd numbers is 2000^2 Note 2000 is 2(10^3). When we square that it is 4x10^6=4000000
The number that is in between 2000 and 3000 is 2500. This number falls exactly halfway between the two given numbers on the number line. It can be calculated by finding the average of the two endpoints: (2000 + 3000) / 2 = 2500.
2000