The width is 4ft the length is 16ft
Yes. I guess it depends on which sidewalk you're talking about.
(20+2w)x(12+2w)-(12x20)=68 w=1
The width would be X, and the length 4 X. Since the perimeter of 40 ft is the two lengths, and the 2 ends, that would be X+X+4X+4X= 40 ft, or 10X= 40 ft, simplified by dividing both sides of the = by 10, to get X=4 and 4X=16.
I believe that the average width of a pencil is 0.25 inchs or 0.6 centimeters.
The width is 4ft the length is 16ft
The average width of a street varies a lot by city and by-law. 40 Feet for the road allotment is a good number though. For example California has a minimum of 40 feet for all city streets. I believe some laws require 64 feet for major roads too.
Yes. I guess it depends on which sidewalk you're talking about.
is that really a question lol.
84
18 inches
32 inches.
(20+2w)x(12+2w)-(12x20)=68 w=1
Length of garden = 2 times its width plus 5 feet Let 2x+5 = length and let x = width Area of sidewalk = 6x = 213 square feet x = 35.5 feet which is the width of the garden 2*35.5+5 = 76 feet which is the length of the garden
The width would be X, and the length 4 X. Since the perimeter of 40 ft is the two lengths, and the 2 ends, that would be X+X+4X+4X= 40 ft, or 10X= 40 ft, simplified by dividing both sides of the = by 10, to get X=4 and 4X=16.
96 to 102 inches in traveling configuration.
A tape measure is commonly used to measure the width and length of a sidewalk. It is important to ensure accurate measurements when planning for repairs or construction work on sidewalks.