An oval is a general word that could have different shapes. If you squash a circle evenly, the new shape in math is called an ellipse, which has an oval shape. The formula for the area of a circle is Pi times the Radius of the circle squared. The radius is half the height of the circle and also half the width of the circle. The general formula for the area of an ellipse is Pi times half the height times half the width. So we say length A is half the height of an ellipse and length B is half the width of an ellipse. When A is equal to B you have a circle. When they are different you have an ellipse. So if you want the area of the circle to be the same as the area of the ellipse, then you have to keep the height times the width the same for the ellipse as it was for the circle. As you squash the ellipse further the width must stretch out more than the height gets pushed down. For example, a circle with radius of 1 inch would have the same area as an ellipse with height ½ inch and width 2 inches because 1 times 1 is equal to ½ times 2. Another ellipse with the same area could have height ¼ inch and width 4 inches.
Not quite sure what you mean by "true way". You can measure it with a string or a similar flexible object. Or you can measure length and width, and - assuming it is an ellipse - use the formula for the circumference of an ellipse - or rather, an approximation formula.
I believe that the average width of a pencil is 0.25 inchs or 0.6 centimeters.
"Oval" can be a variety of shapes. I suggest you use the equation for the area of an ellipse. Assume some convenient ratio of length-to-width.
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An oval is a general word that could have different shapes. If you squash a circle evenly, the new shape in math is called an ellipse, which has an oval shape. The formula for the area of a circle is Pi times the Radius of the circle squared. The radius is half the height of the circle and also half the width of the circle. The general formula for the area of an ellipse is Pi times half the height times half the width. So we say length A is half the height of an ellipse and length B is half the width of an ellipse. When A is equal to B you have a circle. When they are different you have an ellipse. So if you want the area of the circle to be the same as the area of the ellipse, then you have to keep the height times the width the same for the ellipse as it was for the circle. As you squash the ellipse further the width must stretch out more than the height gets pushed down. For example, a circle with radius of 1 inch would have the same area as an ellipse with height ½ inch and width 2 inches because 1 times 1 is equal to ½ times 2. Another ellipse with the same area could have height ¼ inch and width 4 inches.
The width of the average swan is 102 metres.
Earth orbits the Sun in an ellipse; the Sun is in one of the ellipse's focal points. The ellipse's shape, in this case, is quite close to a circle. The average distance from Earth to Sun is about 150 million kilometers.
Not quite sure what you mean by "true way". You can measure it with a string or a similar flexible object. Or you can measure length and width, and - assuming it is an ellipse - use the formula for the circumference of an ellipse - or rather, an approximation formula.
i need to know what is the width of a journal!
I believe that the average width of a pencil is 0.25 inchs or 0.6 centimeters.
No. Both foci are always inside the ellipse, otherwise you don't have an ellipse.
No. Both foci are always inside the ellipse, otherwise you don't have an ellipse.
The semi-major axis.
"Oval" can be a variety of shapes. I suggest you use the equation for the area of an ellipse. Assume some convenient ratio of length-to-width.
It can vary from 3-8 mm in width, on average.
It's technically an ellipse, not a perfect circle. It varies by a few million kilometers; our average orbital radius is 148 million km.