There is not enough information.
Since 7 - 6 = 1 and 7 + 6 = 13, all that can be said is that the base b must satisfy 1 < b < 13.
7X6/2
The area of triangle is : 6.0
57/6= [9.5 cm]
No, it is not possible to have a triangle with sides of 4 cm, 6 cm, and 9 cm. According to the triangle inequality theorem, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 4 cm + 6 cm = 10 cm, which is greater than 9 cm, but 4 cm + 9 cm = 13 cm is greater than 6 cm, and 6 cm + 9 cm = 15 cm is also greater than 4 cm. However, the combination of these lengths does not satisfy the conditions to form a triangle.
24 sq cm
7X6/2
The area of triangle is : 6.0
The length of the hypotenuse of a right triangle with a 13 cm base and a 6 cm height is 14.32 cm
57/6= [9.5 cm]
No, it is not possible to have a triangle with sides of 4 cm, 6 cm, and 9 cm. According to the triangle inequality theorem, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 4 cm + 6 cm = 10 cm, which is greater than 9 cm, but 4 cm + 9 cm = 13 cm is greater than 6 cm, and 6 cm + 9 cm = 15 cm is also greater than 4 cm. However, the combination of these lengths does not satisfy the conditions to form a triangle.
24 sq cm
it can be any height
Area of a triangle = (1/2) x (base) x (height) Can you handle it from there ?
b=5cm/h=6cm
The area of a triangle is calculated using the formula A = 0.5 * base * height. Plugging in the given values, we get A = 0.5 * 14 cm * 6 cm = 42 square cm. Therefore, the area of the triangle is 42 square cm.
That depends not only on the shape, but on how large it is. Any type of figure can be scaled so that it has any desired perimeter.Examples:A triangle with sides 1 cm, 2 cm, 6 cmA triangle with sides 1 cm, 2 cm, 5 cmA triangle with sides 2 cm, 3 cm, 4 cmA nonagon (more correctly an enneagon) with all sides 1 cm
Square root of 45.