The equation you provided appears to be incorrectly formatted. However, if you meant to write the standard form of a circle's equation, which is ((x - h)^2 + (y - k)^2 = r^2), then the center of the circle is given by the point ((h, k)). For the specific equation you intended, please clarify the format, and I can help identify the center accordingly.
What is the center of the circle given by the equation (x- 2)2 + (y + 4)2 = 6?(2, -4)
(-5,3)
At the center, (x, y) = (-2, 5)
(-7,5)
(-4,3)
The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).
The center of the circle is at (-7, 5)
(-5,3)
What is the center of the circle given by the equation (x- 2)2 + (y + 4)2 = 6?(2, -4)
At the center, (x, y) = (-2, 5)
(-7,5)
(-4,3)
Without an equality sign the given terms can't be considered to be the equation of a circle.
(-4,-6)
At the center, (x, y) = (-2, 5)
At the center, (x, y) = (-2, 5)
(8,-8)