What is the center of the circle given by the equation (x-3)2 (y-9)216?

Answer 1

The equation you provided seems to be incorrectly formatted, as it appears to be missing an equal sign and contains unusual notation. If the intended equation is ((x - 3)^2 + (y - 9)^2 = r^2), the center of the circle would be at the point (3, 9). Please clarify the equation if this is not what you meant.