If you mean: (x-3)^2 +(y-9)^2 = 16 then the center of the circle is at (3, 9)
(-5,3)
What is the center of the circle given by the equation (x- 2)2 + (y + 4)2 = 6?(2, -4)
At the center, (x, y) = (-2, 5)
(-4,3)
(-7,5)
The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).
The center of the circle is at (-7, 5)
(-5,3)
What is the center of the circle given by the equation (x- 2)2 + (y + 4)2 = 6?(2, -4)
At the center, (x, y) = (-2, 5)
(-4,3)
(-7,5)
Without an equality sign the given terms can't be considered to be the equation of a circle.
(-4,-6)
At the center, (x, y) = (-2, 5)
At the center, (x, y) = (-2, 5)
(-5, 3)