The incentre, which is the point at which the angle bisectors meet.
It is the largest circle that can be drawn so that it is entirely inside a polygon. In the case of a triangle, its centre is the point where the bisectors of the angles of the triangle meet.
Of course not! There are an infinite number of smaller circles.
Aol
Signifies new beginnings
it becomes a circle inside another circle
The center of the largest circle that you could draw inside a given triangle is going to be at the incenter of the triangle. This is the point where bisectors from each angle of the triangle meet.
It's at the point where the bisectors of the triangle's interior angles meet.
incenter
Well, honey, a circle inside a triangle is usually a symbol used in geometry to represent the incenter of the triangle. The incenter is the point where the angle bisectors of the triangle intersect. So basically, it's just a fancy way of saying the center of the circle is equidistant from all three sides of the triangle. Hope that clears things up for ya!
It is the largest circle that can be drawn so that it is entirely inside a polygon. In the case of a triangle, its centre is the point where the bisectors of the angles of the triangle meet.
Of course not! There are an infinite number of smaller circles.
the incenter of EFG
It is the symbol for Alcoholics Anonymous.
Aol
Signifies new beginnings
it becomes a circle inside another circle
The slant height of a cone is given by the formula , where r is the radius of the circle and h is the height from the center of the circle to the apex of the cone.It is trivial to see why this formula holds true. If a right triangle is inscribed inside the cone, with one leg of the triangle being the line segment from the center of the circle to its radius, and the second leg of the triangle being from the apex of the cone to the center of the circle, then one leg will have length h, another leg will have length r, and by the Pythagorean Thereon, r2 + h2 = d2, and gives the length of the circle to the apex of the cone.