The meridians (lines of longitude) run from the North Pole to the South Pole. The Prime Meridian (zero Longitude) passes through Greenwich, England. Therefore, the answer to your question is the 'North Pole'.
No. All of the meridians merge in a single point at the poles.
No
The position of the specific point of center of mass is the point at which the object could be modeled to have all of its mass acting for all intensive purposes.
There's a simple answer: The earth is a sphere and the parallels are, well, parallel to each other. So obviously the ones closer to the poles are shorter than the ones closest to the Ecuator. As for the meridians all meet at one point ehich are the poles, so they are all the same length.
The North Pole is the center point from which all meridians begin and it is the north extremity of the Earth's axis.
The meridians (lines of longitude) run from the North Pole to the South Pole. The Prime Meridian (zero Longitude) passes through Greenwich, England. Therefore, the answer to your question is the 'North Pole'.
All meridians of longitude converge at the north pole, which is the north extremity of the Earth's rotational axis. They also converge at the south pole, which is the south extremity of the Earth's rotational axis. Neither ponit is the 'beginning' or 'end' of the meridians.
No. All of the meridians merge in a single point at the poles.
All meridians of longitude converge (meet) at the north and south poles.
Of the twelve regular meridians, the yin meridians always flow up the body, and all the yang meridians always flow down.
Some maps are squashed and stretched in such a way that meridians of longitude appear to be parallel (Mercator projection, for example). But the truth is that on the globe, the meridians all converge at the poles, and so they're not parallel.
With the exception of 15 45, all of them. You can travel east around the globe back to the starting point.
All of them do.
All of them
No
The position of the specific point of center of mass is the point at which the object could be modeled to have all of its mass acting for all intensive purposes.