It works out that the centre of the circle is at (-0.5, 1.5) and its diameter is the square root of 28
The answer depends on what pb and cp are!
The centre is (a, a) and the radius is a*sqrt(2).
A circle, centre (0,0), radius = 5
Centre = (0,0), the origin; radius = 11
Equation of a circle centre the origin is: x2 + y2 = radius2 ⇒ radius = √9 = 3.
The answer depends on what pb and cp are!
The centre is (a, a) and the radius is a*sqrt(2).
A circle, centre (0,0), radius = 5
Centre = (0,0), the origin; radius = 11
Equation of a circle centre the origin is: x2 + y2 = radius2 ⇒ radius = √9 = 3.
If: x^2 +y^2 = 12x -10y -12 Then: x^2 +y^2 -12x +10y +12 = 0 Completing the squares: (x-6)^2 +(y+5)^2 = 49 which is the radius squared Center of circle: (6, -5) Diameter of circle: 14 units
The centre is (-5, 3)
The equation describes a circle with its centre at the origin and radius = √13. Each and every point on that circle is a solution.
For all circles , however, large or small The diameter is twice the radius. Diameter(d) equals(=) radius(r) plus(+) radius(r). d = r + r d = 2r . NB The diameter is a straight line from the circumference to the centre , and then out to the opposite sided circumference. It is NOT an angled line centred on the central point.
The centre is (3,-1) and the radius is sqrt(10).
5. A circle with centre (0,0) has equation: x2 + y2 = radius2 With: x2 + y2 = 25 = 52 The radius is 5.
A circle centre (0, 0) and radius r has equation x² + y² = r² The circle x² + y² = 36 has: r² = 36 → radius = 6