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The odds against winning 5 in a lottery game are 179 to 2 What is the probability of winning?
If the odds are 179 to 2, the probability of winning is 0.01105, or; the chance of winning is 1.11%
What are the odds of rolling either a 1 or a 5 with 3 dice?
well there are 6 sides and the odd of hitting one is a 1 out of 6 chance. the odds of hitting five is a 5 out 6 chance
Solve mathematically Raffles selling 100 tickets in each Which would give me better odds of winning something buy one ticket in each of the five raffles or buy five tickets in one?
Either way you are buying 5 tickets out of 500. That means that the probability of winning is 5/500 = 1/100 = 1%
A team has the probability of winning one out of every six games What is the minimum number of games the team should play to have a fair chance of winning atleast one game?
A fair chance of winning is more than 50% chance of winning. Therefore probability = 0.5 We need to find a fair chance of winning atleast one match. 1-(5/6)^n > 0.5 hence, n=4 QED (quite easily done, :-p)
What are the odds of rolling a 5 with just one roll of a die?
on a 6-sided die theres a 1/6 chance
The odds against winning 5 in a lottery game are 179 to 2 What is the probability of winning?
If the odds are 179 to 2, the probability of winning is 0.01105, or; the chance of winning is 1.11%
What is probability if odds are 5 to 3?
For 5 to 3 odds of winning; the probability of winning is 0.375 or 37.5%
What is probability a horse will win a race if it has odds of 5 to 1?
5 to 1 to win means the probability of actually winning is 1 to 5, or 0.2. The larger the payout, the longer (or poorer) the odds. Actually, 5 to 1 means 1 chance in 6 or 16.7%. Of course, race track odds may not be the true probablity of winning.
How you can find the brobability as a fraction?
I assume the probability is given a percent, or as odds, i.e. there's a 20% chance or 1 in 5 chance. You convert a percent by dividing by 100, 20% = 0.20, you convert odds by dividing the first number by the second, ie: 1/5 = 0.20.
What are the odds of rolling either a 1 or a 5 with 3 dice?
well there are 6 sides and the odd of hitting one is a 1 out of 6 chance. the odds of hitting five is a 5 out 6 chance
Solve mathematically Raffles selling 100 tickets in each Which would give me better odds of winning something buy one ticket in each of the five raffles or buy five tickets in one?
Either way you are buying 5 tickets out of 500. That means that the probability of winning is 5/500 = 1/100 = 1%
If you play 276 spins of Roulette an hour and 0.04 percent of the time you lose what chance as a percentage per hour do you have of not losing over a nine hour period?
What the previous person said is incorrect, the lowest percentage of winning, at least on a double zero wheel is 2.63%, there is no 0.04 percent chance. so therefore every single spin if you bet on one number would be 2.63% chance of winning, out of all 276 spins your odds would still be 2.63% chance of winning in total, keep in mind one number pays 35 to 1 so if you bet 5 dollars and won, you would have 175 dollars, and you would have 35 chances to break even. No chance, because if 0.04% of the time you lose, you're losing all of the time. The odds, however, in roulette stay fixed, so at any one time, you'd have a 99.96% chance of winning with those odds.
There is 32 balls in a lotto machine what is the change of win division 1 if you need 5 winning numbers?
the odds are calculated by multiplying the number of balls in sequence... for a 5 number win it would be 32x31x30x29x28.... to 1. the draw of your first number is 32:1 odds... your second number then becomes 31:1 odds and so on... or you have 1 chance in 24,165,120 to hit 5 numbers from a 32 ball machine
If the odds in favor of Rangers winning the game are 7 to 5 what is the probability that they will win?
The probability is 0.416667 or 41.67%
How do you calculate your odds of winning at lotto if you spend 1 dollar on an entry?
Odds are expressed as a ratio of probability of winning versus probability of not winning. Consider a simple example of tossing a fair dice where you "win" if it lands on three. P(three):P(not three) = (1/6) : (5/6) = 1:5 . So your odds of winning are 5 to 1 against. Now let's imagine to win lotto you need to guess 6 numbers correctly out of 45 and each guess costs $1. Probability of winning (from 1 guess) = 1/(45 x 44 x 43 x 42 x 41 x 40) = 0.000000000171 Probability of not winning = 1-P(winning) = 0.999999999829 So the odds are 0.000000000171:0.999999999829 = 1:5,864,443,199 or just under 6 billion to 1 against!
A team has the probability of winning one out of every six games What is the minimum number of games the team should play to have a fair chance of winning atleast one game?
A fair chance of winning is more than 50% chance of winning. Therefore probability = 0.5 We need to find a fair chance of winning atleast one match. 1-(5/6)^n > 0.5 hence, n=4 QED (quite easily done, :-p)
What are the odds of rolling a 5 with just one roll of a die?
on a 6-sided die theres a 1/6 chance
