Before tackling this one, I must clean it up a bit.
-- I'll assume that the floor is horizontal under the box.
-- "Angle" means the difference between two directions, but the question specifies
only one of them ... the direction of the rope. I'll assume that the 60° is the angle
between the rope and the horizontal travel of the box, and that the rope and the
tension in it are both directed above the horizontal, i.e., sloped toward the ceiling,
not toward the floor.
Now we have something we can work with.
-- The horizontal component of the tension in the rope is 80 cos(60) = 40 N.
-- The box is sliding along at constant speed, so the horizontal forces on it are balanced.
That means that the friction force is also 40 N but backwards.
-- The weight of the box is (m g) = (10 x 9.8) = 98 N.
-- The coefficient of friction is friction force/weight = 40/98 = 40.8 %
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Why this solution is bogus, at least in part:
The other component of the tension in the rope ... the vertical one ... is 80 sin(60) = about 69.3 N.
That force is applied to the box at the point where the rope connects, and pulls
straight up at that point. Its effect must be to reduce the box's apparent weight
at that end, and by some complicated amount everywhere along the length of the
box. So the force of friction is also distributed along the length of the box in some
non-uniform and complicated way, and the aggregate apparent coefficient of friction
is some ugly integral of the contributions due to an element of weight at every
element of length/area from one end of the box to the other.
Am I over-thinking this ? ? Perhaps it would be best if I take a nap.
No. It is the change in velocity (not speed) during a given interval of time. It can be an increase or a decrease although a decrease is also called a deceleration.The distinction between velocity and speed can best be illustrated by an object going round in a circle at a constant speed. It is changing direction all the time so that its velocity is constantly changing. It is constantly accelerating even though it is travelling at constant speed.
Initial velocity is 10 m/s in the direction it was kicked. Final velocity is 0, when friction and air resistance finally causes it to come to a halt.
If the Object is falling at a constant velocity the shape of the graph would be linear. If the object is falling at a changing velocity (Accelerating) the shape of the graph would be exponential- "J' Shape.
Equations relating to conyeyor belt length, friction, lag, and velocity may be found at the indicated link(s).
v = vo + gt = 2(m/s) + 9.8(m/s2) x 5s = 51(m/s)
It determines your terminal velocity, depending on your drag coefficient.
When an object is moving at a constant velocity, it means that the forces acting on it are balanced. In this case, the force of kinetic friction is equal and opposite to the applied force, making it easier to calculate the coefficient of kinetic friction using the known values of force and normal force.
The strength of the force of friction depends on the types of surfaces involved and on how hard the surfaces push together.
To calculate the friction in a pulley, you can use the formula: Friction = ยต * N, where ยต is the coefficient of friction and N is the normal force acting on the pulley. The coefficient of friction represents how "rough" the surfaces in contact are. By multiplying the coefficient of friction with the normal force, you can determine the amount of friction in the pulley system.
The coefficient of friction for air flow in a round duct is typically around 0.02. This coefficient may vary depending on factors such as surface roughness and airflow conditions.
The factors that affect the coefficient of static friction include the roughness of the surfaces in contact, the normal force pressing the surfaces together, and the presence of any intermolecular forces between the surfaces. Additionally, the temperature and cleanliness of the surfaces can also influence the coefficient of static friction.
To keep a block at a constant velocity, you need to apply a force equal in magnitude but opposite in direction to the force of friction acting on the block. This force is called the kinetic friction force and is dependent on the coefficient of friction between the block and the surface it's on.
The coefficient of kinetic friction depends on the surfaces in contact and the roughness of those surfaces. It is a constant for a given pair of surfaces in contact and is independent of factors like velocity and normal force.
The force needed to slide the crate at constant velocity is equal in magnitude but opposite in direction to the force of friction. The force of friction can be calculated as the product of the coefficient of friction and the normal force acting on the crate (weight of the crate). Therefore, the force needed would be 250 kg * 9.8 m/s^2 * 0.25 = 612.5 N.
The force needed to slide the mass at a constant velocity is equal in magnitude and opposite in direction to the frictional force. The frictional force is calculated as the coefficient of friction multiplied by the normal force (frictional force = coefficient of friction * normal force). Hence, the force needed would be 0.43 times the weight of the mass (force = coefficient of friction * mass * gravity).
The average value of the coefficient of velocity for a submerged orifice is typically around 0.97 to 0.99. This value represents the efficiency of the orifice in converting the potential energy of the fluid into kinetic energy.
True. An object in circular motion is constantly changing direction, which means it is constantly accelerating. This acceleration is called centripetal acceleration and is always directed towards the center of the circular path.