Q: What is the coefficients 15b plus 23b plus 10?

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Find two numbers that add up to make 7 (the coefficient of the second term) and which multiply to make 10 (the product of the coefficients of the first and last terms - 1*10): x2 + 7x + 10 = x2 + 5x + 2x + 10 = x(x + 5) + 2(x + 5) = (x + 2)(x + 5)

10 + 10 + 10 + 5 + 5 +1 = 41.

10 X 10 = 100 You can do this four ways: You can do it mentally in your head or you can add them all up on paper by lining up the numbers correctly with each other. You can use a calculator and that is the easiest way. An alternate way is to multiply 10 by 10.

10 + 10 + 10 = 30

18 + 10 + 28 + 10 = 66

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If you mean 'simplify': (3x + 5)/15 I simply divided the coefficients (numbers) by 2.

12b - 5 = 15b + 5 subtract 12b from both sides 12b - 12b - 5 = 15b - 12b + 5 - 5 = 3b + 5 subtract 5 from each side - 5 - 5 = 3b + 5 - 5 - 10 = 3b divide both sides integers by 3 - 10/3 = (3/3)b - 10/3 = b ---------------------check in original equation ( change whole numbers to fractions of common denominations ) 12(-10/3) - 15/3 = 15(-10/3) + 15/3 - 120/3 - 15/3 = - 150/3 + 15/3 - 45 = - 45 checks

Find two numbers that add up to make 7 (the coefficient of the second term) and which multiply to make 10 (the product of the coefficients of the first and last terms - 1*10): x2 + 7x + 10 = x2 + 5x + 2x + 10 = x(x + 5) + 2(x + 5) = (x + 2)(x + 5)

The original brochure can be found here: http://brochures.slosh.com/It appears the standard size was E78-15B which converts to a P195/75R15Some of the optional sizes were 7.00-15C, 6.50-16C, 10-16.5C, G78-15B, H78-15B, and L78-15B.http://www.turbinecar.com/tires.htm has a very thorough list of conversion tables to obtain modern size equivalents.

45

700.

10 + 10 + 10 + 10 + 10 + 10 + 10 + 108 = 178

10 + 10 + 10 + 10 + 10 = 50

10 + 10 + 10 + 10 + 10 + 10 = 60 10 X 6 = 60

10 + 10 + 10 + 10 = 40

25+10+10+10+1+1= 57

10 + 10 + 10 + 5 + 5 +1 = 41.