If the first term is 12 and the seventh term is 36, then we have gone up 36-12 in the space of 6 term changes. This is 24 per 6 changes, which can be written as the division 24/6. This works out as 4. Thus the common difference in the sequence is 4.
What is the 14th term in the arithmetic sequence in which the first is 100 and the common difference is -4? a14= a + 13d = 100 + 13(-4) = 48
16
The way of asking the question is wrong. It is known as common difference not common ratio. Here a = 1 , d= 3 a7=? we know that , an = a + (n-1)d a7= 1 +6x3= 19
6
-8
a + 99d where 'a' is the first term of the sequence and 'd' is the common difference.
What is the 14th term in the arithmetic sequence in which the first is 100 and the common difference is -4? a14= a + 13d = 100 + 13(-4) = 48
It is a + 8d where a is the first term and d is the common difference.
16
The way of asking the question is wrong. It is known as common difference not common ratio. Here a = 1 , d= 3 a7=? we know that , an = a + (n-1)d a7= 1 +6x3= 19
You subtract any two adjacent numbers in the sequence. For example, in the sequence (1, 4, 7, 10, ...), you can subtract 4 - 1, or 7 - 4, or 10 - 7; in any case you will get 3, which is the common difference.
From any term after the first, subtract the preceding term.
6
The common difference is 6; each number after the first equals the previous number minus 6.
6
6
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