The following answer is correct only if b is the measure of an angle in degrees.
The complement is 90-43 = 47 degrees.
Whatever you do to one side of the equation (equals sign), you must do to the other: 43 - b = 24 ⇒ 43 - b + b = 24 + b ⇒ 43 = 24 + b ⇒ 43 - 24 = 24 + b - 24 ⇒ 19 = b So b is 19.
(A' ∩ B') = (A È B)'
30 is the answer A+ student raynaray
5x - 9y = 43 (A)3x + 8y = 68 (B)(A)*3: 15x - 27y = 129(B)*5: 15x + 40y = 340Subtracting the first from the second gives67y = 211 => y = 211/67 = 3.15 approxSubstituting the [rational] value of y in (B)5x - 9*211/67 = 43 => 5x = 43 + 1899/67 = 4780/67therefore x = 956/67 = 14.27 approx.
With the information that is available from the question, it is impossible.
180
b
complement of c
Whatever you do to one side of the equation (equals sign), you must do to the other: 43 - b = 24 ⇒ 43 - b + b = 24 + b ⇒ 43 = 24 + b ⇒ 43 - 24 = 24 + b - 24 ⇒ 19 = b So b is 19.
X=30 degrees
B=26 you just have to isolate the variable, so subtract 17 from 43 because the rule in algebra is that whatever you do to one side, you have to do to the other
(A' ∩ B') = (A È B)'
In a triangle a/SinA = b/SinB = c/SinC Since angle A = 43 and angle C is 72, angle B = (180) - (72 + 43) = 65 Hence 20/Sin65 = c/Sin72 20/0.9063 = c/0.9510 c = (20 x 0.9510)/0.9063 = 20.9864
30 is the answer A+ student raynaray
The complement of a subset B within a set A consists of all elements of A which are not in B.
67 degrees
P(A given B')=[P(A)-P(AnB)]/[1-P(B)].