The following answer is correct only if b is the measure of an angle in degrees.
The complement is 90-43 = 47 degrees.
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β 11y agoWhatever you do to one side of the equation (equals sign), you must do to the other: 43 - b = 24 ⇒ 43 - b + b = 24 + b ⇒ 43 = 24 + b ⇒ 43 - 24 = 24 + b - 24 ⇒ 19 = b So b is 19.
(A' ∩ B') = (A È B)'
30 is the answer A+ student raynaray
5x - 9y = 43 (A)3x + 8y = 68 (B)(A)*3: 15x - 27y = 129(B)*5: 15x + 40y = 340Subtracting the first from the second gives67y = 211 => y = 211/67 = 3.15 approxSubstituting the [rational] value of y in (B)5x - 9*211/67 = 43 => 5x = 43 + 1899/67 = 4780/67therefore x = 956/67 = 14.27 approx.
Since the angles are complementary, [ A + B = 90 ], so we can substitute (90-B) wherever we see 'A'.The question tells us that [ A - B = 22 ]Make the substitution for ' A ':(90 - B) - B = 2290 - 2B = 22-2B = -682B = 68B = 34A = 56
180
b
complement of c
Whatever you do to one side of the equation (equals sign), you must do to the other: 43 - b = 24 ⇒ 43 - b + b = 24 + b ⇒ 43 = 24 + b ⇒ 43 - 24 = 24 + b - 24 ⇒ 19 = b So b is 19.
X=30 degrees
b + 17 = 43 Subtract '17' from both sides b + 17 - 17 = 43 - 17 b = 26
(A' ∩ B') = (A È B)'
The complement of a subset B within a set A consists of all elements of A which are not in B.
In a triangle a/SinA = b/SinB = c/SinC Since angle A = 43 and angle C is 72, angle B = (180) - (72 + 43) = 65 Hence 20/Sin65 = c/Sin72 20/0.9063 = c/0.9510 c = (20 x 0.9510)/0.9063 = 20.9864
30 is the answer A+ student raynaray
P(A given B')=[P(A)-P(AnB)]/[1-P(B)].
a + b = 90, ie a = 90 - b;a = 2b - 36 so 2b - 36 = 90 - b ie 3b = 126 so b = 42 and a = 48 (which is 36 less than 84)