To factor the polynomial ( x^3 - 2x^2 + x - 2 ), we can first group the terms: ( (x^3 - 2x^2) + (x - 2) ). Factoring out common terms gives us ( x^2(x - 2) + 1(x - 2) ). This allows us to factor further, resulting in ( (x - 2)(x^2 + 1) ). Thus, the complete factorization is ( (x - 2)(x^2 + 1) ).
To factor the polynomial (2x^2 + 20x + 50), first, we can factor out the greatest common factor, which is 2. This gives us (2(x^2 + 10x + 25)). The quadratic (x^2 + 10x + 25) can be factored further as ((x + 5)^2). Thus, the complete factorization of the polynomial is (2(x + 5)^2).
(x + 5)(x + 2)
(-2x3 - 2x2 + 12x) = -2x (x2 + x - 6) = -2x (x + 3) (x - 2)
To factor the polynomial ( x^3 - 3x^2 + x - 3 ), we first apply the Rational Root Theorem and test possible rational roots. After testing, we find that ( x = 3 ) is a root. Using synthetic division, we divide the polynomial by ( (x - 3) ) to obtain ( x^2 + 1 ). Thus, the complete factorization is ( (x - 3)(x^2 + 1) ).
That would be -2 (x-2) x (x+3). Click on the Wolfram|Alpha link for all of your polynomial factorization needs.
It is (x+2)(x+9) when factored
(x + 2)(3x + 1)
To factor the polynomial (2x^2 + 20x + 50), first, we can factor out the greatest common factor, which is 2. This gives us (2(x^2 + 10x + 25)). The quadratic (x^2 + 10x + 25) can be factored further as ((x + 5)^2). Thus, the complete factorization of the polynomial is (2(x + 5)^2).
It is 6x(2x+5) when factored
(x + 5)(x + 2)
x3 - 12x2 + 35x = x (x2 - 12x + 35) = x (x - 7) (x - 5)
(-2x3 - 2x2 + 12x) = -2x (x2 + x - 6) = -2x (x + 3) (x - 2)
To factor the polynomial ( x^3 - 3x^2 + x - 3 ), we first apply the Rational Root Theorem and test possible rational roots. After testing, we find that ( x = 3 ) is a root. Using synthetic division, we divide the polynomial by ( (x - 3) ) to obtain ( x^2 + 1 ). Thus, the complete factorization is ( (x - 3)(x^2 + 1) ).
x² + 8x + 15 = (x + 5)(x + 3)
x + 12x + 20 = (x + 10)(x + 2)
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