2x+y=0.
The x-intercept is the point where y=0 and the y-intercept is the point where x=0.
If x is 0, the given equation becomes 2(0)+y=0. This is the same as y=0, so the coordinates of the x-intercept are (0,0).
Usually, you would plug in y=0 and find x to find the x-intercept. However, since y=0 for the x-intercept, we know that x=0 when y=0 (given that the function crosses the y-axis at only 1 point. We know this because this is a linear function that is not parallel to x=0.).
The coordinates of the x intercept for the equation y equals x plus 1 is (x=-1, y=0).
2y = 4x + 3At the x-intercept, y=0.0 = 4x + 34x = -3x = -3/4The coordinates of the point are (-3/4 , 0)
The x-intercept is (15 0)
The y intercept will be where the x-coordinate is zero, so set x=0 in the equation and you have: 0 + y = -9, or y = -9. Coordinate (0,-9)
Solving the equation for "y" gives you the slope-intercept form.
The coordinates of the x intercept for the equation y equals x plus 1 is (x=-1, y=0).
2y = 4x + 3At the x-intercept, y=0.0 = 4x + 34x = -3x = -3/4The coordinates of the point are (-3/4 , 0)
The x-intercept is (15 0)
The y intercept will be where the x-coordinate is zero, so set x=0 in the equation and you have: 0 + y = -9, or y = -9. Coordinate (0,-9)
Solving the equation for "y" gives you the slope-intercept form.
It is 18 and the y intercept is 3
b
When finding the y-intercept, plug in x=0 y = 4x + 2 y = 4(0) + 2 y = 2 So your intercept is (0,2)
in the equation: y=mx+b , the y-intercept is represented by "b".
x+2y=8 The x-intercept is the value of x when y=0, therefore substitute y=0 into the equation: x+0=8 therefore, x=8 The coordinates of this point is (8,0)
Yes, that is the slope intercept form of the equation for a straight line.
The y intercept is 6