Al(s) | Al3+(aq) Zn2+(aq) | Zn(s)
The balanced equation for the reaction of phosphoric acid (H3PO4) and aluminum (Al) is: 2Al + 3H3PO4 → 3H2 + 2AlPO4
The balanced equation for the reaction of magnesium metal with aluminum ions is: 2Al^3+ + 3Mg -> 2Al + 3Mg^2+. In this reaction, magnesium metal displaces aluminum ions to form aluminum metal and magnesium ions.
The net ionic equation has only the species involved in the chemical reaction.
Type your answer here... Al3+(aq) + 3e- Al(s) and Au(s) Au+(aq) + e-
Yes, a reaction will occur in which aluminum will displace zinc from the zinc nitrate solution. This is due to the higher reactivity of aluminum compared to zinc. The result will be the formation of aluminum nitrate and zinc metal.
The electrolysis of molten aluminum chloride involves the migration of Al3+ and Cl- ions to the respective electrodes. At the cathode, aluminum ions are reduced to form aluminum metal, while at the anode, chloride ions are oxidized to form chlorine gas. The overall reaction can be represented as 2Al3+ + 6e- -> 2Al (reduction at cathode) and 2Cl- -> Cl2 + 2e- (oxidation at anode).
6H3O+ + 2Al --> 2Al3+ + 3H2 + 6H2O[Chloride ions (Cl -) are left out of equation, don't take part in reaction: 'tribune' ions].
Aluminum oxide does not react with water! Not under normal conditions anyway. That's why aluminum metal doesn't corrode -- but a thin aluminum oxide layer builds up and protect the outer surface.That being said, it can react with water in acidic conditions to produce Al3+ ions.Al2O3(s) + 6H(aq) --> 2Al3+(aq) + 3H2O(l)
.... between one or more postive (metal) ions and one or more negative ions like chloride, sulfate, nitrate, carbonate etc. Example: 2Al3+ + 3SO42- --> Al2(SO4)3
The aluminum metal appears to be turning into copper, but it is actually just removing the metallic copper from its compound state. The Aluminum is oxidized and loses e-, becoming Al 3+ and the copper ions are reduced (they accept those e-) to form solid copper precipitate. The aluminum ions and chloride ions remain in the solution. The reaction will only occur in water and occurs because the transfer of electrons from the aluminum to the copper results in a more stable system.
The two are highly reactive when mixed in water. If you add aluminum to a water solution of copper chloride, the aluminum will be combined as aluminum chloride gas, releasing the copper into the water. The mixture will turn very hot, bubble up, and start to smoke, and the color will change from blue to dark red. ========================= The first sentence is correct, the two are highly reactive, but from there on, there are problems... There's no such thing as aluminum chloride gas. There is a gas given off, but it is hydrogen gas. The "smoke" is actually tiny droplets of water condensed from water vapor. It gets that hot. The red color is due to the formation of copper metal a Cu2+ ions are reduced to the metal as aluminum metal is oxidized. Aluminum metal has a thin coating of aluminum oxide, Al2O3, covering the surface. Even freshly scraped aluminum metal will quickly reform the passivating layer of aluminum oxide. So in many solutions, the layer of Al2O3 prevents any aluminum metal from reacting. If aluminum metal is placed in a solution of copper(II) sulfate, you will not get a reaction. No copper metal will form on the aluminum. But when placed in copper(II) chloride, aluminum will give a vigorous reaction with a lot of heat and hydrogen gas being given off. The reason is the chloride ion. In the presence of chloride ion, the Al2O3 layer dissolves forming the AlCl4^- in solution and exposing a fresh layer of aluminum metal. The aluminum metal will reduce copper(II) ions to copper metal, AND the aluminum metal will react with water very much like an alkali metal reacts with water, vigorously, with a lot of heat given off, and with the formation of hydrogen gas. Al2O3 + 8Cl- + 3H2O --> 2AlCl4^- + 6OH- Al(s) + OH- + 2H2O --> Al(OH)3(s) + H2(g) 2Al(s) + 3Cu2+ --> 2Al3+ + 3Cu(s)
Aluminum*)oxide is an amphoteric compound by being both 1. acidic and 2. alkaline1. acidicIt will dissolve in hydroxide (an alkaline solution):Al2O3 + 2OH- + 3H2O --> 2 Al(OH)4- aluminate anion2. alkalineIt will dissolve in acidic H+ solution:Al2O3 + 6H+ --> 2Al3+ + 3H2OThe amphoteric, neutral formula can be written as both Al2O3.(H2O)3 and: 2Al(OH)3Added(The same answer, but this time written without ions in solvent):Aluminium*)oxide is amphoteric:Al2O3(s) can react with a base:Al2O3(s) + 2NaOH(aq) + H2O(l) --> 2NaAl(OH)4(aq)Aluminium oxide + sodium hydroxide + water --> sodium aluminateAl2O3 can react with an acid:Al2O3(s) + 6HCl(aq) --> 2AlCl3(aq) + 3H2O(l)Aluminium oxide + hydrochloric acid --> aluminum chloride + water*) The USA spells Al as aluminum; British Isles as aluminum. Both are correct.