49.8436 to 3 sig fig is 49.8
The 3 digits starting with the first non-zero digit is 49.8
The next digit is 4 which is less than half way to 10, so do not add 1 to last digit (with carry), ie leave answer as 49.8
4 is a whole number and can never be a decimal.
1.0*103
It is: 5/9 = 0.55555 ..... recurring or as 0.56 to two significant figures
1) How did you come across such a big number?2) In 10 significant figures, the scientific form of the answer = 2.663730488x1090
70,206To be technically correct, the word "and" doesn't belongin the spoken form of the number.
0.001 in standard form is 1*10-3. The original number may not be correct to 3 significant figures, but if it is, it should have been written as 0.00100 to indicate the degree of precision. In that case the standard form would be 1.00*10-3.
i wish i knew! obviously doing the same maths question!
1500m is already in a form with two significant figures.
(4.6 x 10)-7 x (7.2 x 1014)
Four, assuming that 7.000 is written in that form to indicate that it has 4 significant figures.
The two mean different things; we couldn't tell you which is correct unless you told us what you were trying to mean.If you want to convey that you're sure of four significant figures, then 20.10 is the correct form.
4 is a whole number and can never be a decimal.
1.0*103
3.528005 * 106 - not much of an advantage if you keep to 6 significant figures.
It is: 5/9 = 0.55555 ..... recurring or as 0.56 to two significant figures
1) How did you come across such a big number?2) In 10 significant figures, the scientific form of the answer = 2.663730488x1090
70,206To be technically correct, the word "and" doesn't belongin the spoken form of the number.