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The method used is usually to isolate the value being solved for on the left hand side of the equation
so, when we are told that
a = 2bc - d
we switch the equation around and get
2bc - d = a
Then we add 'd' to each side and get
2bc = a + d
Then we divide both sides by '2b' and get
c = (a + d) / 2b
What else can I help you with?
Which of these formulas is correctly rewritten from the original formula to solve for d a equals 2bc plus d?
d=a-2bc
A equals 2bc plus d solve for d?
d = a - 2bc
Which of these formulas is correctly rewritten from the original formula to solve for c if a equals 2bc - d?
(a+d)/2b=c
What is the original formula to solve for b in this problem a equals 2bc plus b?
Not sure about the original formula, but one that works is b = a/(2c + 1)
What formula is correctly rewritten from the original formula to solve for d?
d = a - 2bc
Which of these formulas is correctly rewritten from the original formula to solve for d a equals 2bc plus d?
d=a-2bc
A equals 2bc - d what is the formula to solve for c?
Type your answer here... a = 2bc-d add d to both sides a + d = 2bc divide both sides by 2b (a+d)/2b = c
A equals 2bc plus d solve for d?
d = a - 2bc
What formula is correctly rewritten from the original formula a 2bc d to solve for d?
d = a - 2bc
Which of these formulas is correctly rewritten from the original formula to solve for b a equals 2bc plus d?
If a=2bc+db= (a - d) / 2c If a=2b+c b=1/2(a-c)
Which of these formulas is correctly rewritten from the original formula to solve for c if a equals 2bc - d?
(a+d)/2b=c
A equals 2bc - d how do you rewrite the original formula to solve for c?
A = 2bc - dAdd 'd' to each side of the equation:A + d = 2bcDivide each side by 2b :(A + d)/2b = c
What is the original formula to solve for b in this problem a equals 2bc plus b?
Not sure about the original formula, but one that works is b = a/(2c + 1)
Which of these formulas is correctly rewritten from the original formula to solve for c a equals 2bc - d?
c= (a+d) / 2b
What formula is correctly rewritten from the original formula to solve for d?
d = a - 2bc
Is Z equals 1A plus 2BC plus 3D a linear programming objective function?
No. 1a and 3d are linear, but 2bc is not. ■
Which formula for a 2bc d is correctly rewritten from the original formula to solve for b?
None.
