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(2 + 4i) - (7 + 4i) = -5 2 + 4i - 7 + 4i = -5 + 8i
Since the imaginary parts cancel, and the real parts are the same, the sum is twice the real part of any of the numbers. For example, (5 + 4i) + (5 - 4i) = 5 + 5 + 4i - 4i = 10.
sqrt(-752) = 4i sqrt(47) i = sqrt(-1)
The multiplicative inverse of a number a is a number b such that axb=1 If we look at (3-4i)/(5+2i), we see that we can multiply that by its reciprocal and the product is one. So (5+2i)/(3-4i) is the multiplicative inverse of (3-4i)/(5+2i)
7
(2 + 4i) - (7 + 4i) = -5 2 + 4i - 7 + 4i = -5 + 8i
-6-4i.
(x - 4i)(x + 4i) where i is the square root of -1
-9
The conjugate of -8-4i is -8+4i. It is obtained by changing the sign of the imaginary part of the complex number.
When finding the conjugate of a binomial, you just reverse the sign. So the conjugate of 3+4i is 3-4i.
4i(-2 -3i) = 4i×-2 - 4i×-3i = -8i -12i² = -8i + 12 = 12 -8i → the conjugate is 12 + 8i
To get the conjugate simply reverse the sign of the complex part. Thus conj of 7-4i is 7+4i
The multiplicative inverse of a complex number is found by taking the reciprocal of the number. In this case, the reciprocal of 4i is -1/4i. To find the reciprocal, you divide 1 by the complex number, which results in -1/4i. This is the multiplicative inverse of 4i.
Add the real and the imaginary parts separately.
-4, +4, -4i and 4i
To solve this problem, we first need to understand that "four times the number i" can be represented as 4i. Then, to find "12 fewer hats than 4i," we subtract 12 from 4i to get 4i - 12. Therefore, "12 fewer hats than four times the number i" is represented by the expression 4i - 12.