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Q: What is the critical angle for light traveling from water into air?
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Is there a critical angle for light traveling from glass to water?

Yes, there is a critical angle for light traveling from glass to water. This critical angle is the angle of incidence that results in light being refracted along the interface between the two mediums, rather than being transmitted into the other medium. The critical angle can be calculated using Snell's Law.


When do you have critical angle?

A critical angle refers to the highest angle the light can possibly refract into or between objects without disappearing. ie = light going from crystal into water, the critical angle is 47degrees.


What Critical angle of light passing from glass to water is minimum from?

The critical angle of light passing from glass to water is minimum when the light is passing from a denser medium (glass) to a rarer medium (water), which is when the light travels along the normal. At this orientation, the critical angle is the smallest possible value for the glass-water interface.


What is the critical angle of perspex and water?

The critical angle for perspex and water is approximately 41 degrees. This means that any light ray entering perspex from water at an angle greater than 41 degrees will be totally internally reflected within the perspex.


A ray of light traveling from air to water is incident at an angle of 64 degrees Part of the light is reflected at an angle of what?

It is reflected at exactly the same angle, but on the other side of the normal at the point of incidence.


As a ray of light passes from air into glass the angle it makes with the surface normal will?

Decrease if the light is entering the glass at an angle greater than the critical angle, and increase if the light is entering the glass at an angle less than the critical angle. The angle the ray makes with the surface normal is known as the angle of refraction.


What happens to a light wave traveling through a diamond that strikes a boundary with water at a 45 degree angle?

When a light wave traveling through a diamond strikes a boundary with water at a 45 degree angle, it will refract as it enters the water due to the change in medium density. Some of the light will also reflect off the boundary between the diamond and water, causing partial reflection and transmission of the light wave.


Why critical angle for water is greater than the critical angle of glass?

Because of the difference in the density of the materials.


What happens to a light wave traveling through air when it strikes a boundary with water at a 45 and Acirc and deg angle?

When a light wave traveling through air strikes a boundary with water at a 45° angle, it will change speed and direction due to a change in the medium's refractive index. This phenomenon is called refraction. The angle of refraction depends on the refractive indices of air and water according to Snell's law.


What happens to light that enters the water?

When light enters water, it can be absorbed, reflected, or refracted. Some light is absorbed by the water molecules, causing it to heat up. Other light can be reflected back at the surface if the angle of incidence is greater than the critical angle. Finally, light can be refracted as it changes speed while passing from air to water, causing it to change direction.


Does water reflect or refract and why?

Water can both reflect and refract light. When light hits the surface of water at an angle, some of it is reflected back and some is refracted, or bent, as it passes through the water due to the change in medium. The amount of reflection and refraction depends on the angle of incidence and the refractive index of water.


What is the critical angle of glass?

When light in glass of index of refraction n hits the surface at angle A relative to the surface normal (perpendicular line to the surface) it generally exits into the air at larger angle B. These three variables are related by Snell's Law: n Sin(A) = (1)Sin(B) (air has index of refraction approx. = 1 ) The critical angle A for internal reflection occurs when the exit angle is 90 so the exit light skims the surface. Anything larger then critical A and the light gets reflected back into the glass. So in Snell's law let B = 90; nSin(A) =(1)Sin(90) = (1)(1) so Sin(A) = 1/n For glass n ~ 1.5 so Sin(A) ~ .67 This is the sine of the critical angle. Now figure out what angle has a sign of .67 and Whala you have it.