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Suppose x3 = -64 then x3 + 64 = 0
So (x + 4)*(x2 - 4x + 16) = 0
So x = 4 or x = 2 +/- 2i*sqrt(3) where i is the imaginary square root of -1.

-4 * -4 * -4 = -64

So cube root of -64 = -4

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Wiki User

15y ago

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Wiki User

16y ago

cubed root of 64 is "4"!!!!

:D

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Wiki User

12y ago

The cube root of 6.4 is 1.8566355334451115

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Wiki User

8y ago

Cube root of 64=4

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Wiki User

15y ago

(-4)3 = -64

so the answer is -4

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Wiki User

14y ago

The cubed root of 64 is 4. 4x4x4=64

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Wiki User

14y ago

Four.

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Wiki User

15y ago

4.

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Q: What is the cube root of -64?
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