Suppose x3 = -64 then x3 + 64 = 0
So (x + 4)*(x2 - 4x + 16) = 0
So x = 4 or x = 2 +/- 2i*sqrt(3) where i is the imaginary square root of -1.
-4 * -4 * -4 = -64
So cube root of -64 = -4
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cube root of 64 = 4 4 x 4 = 16, and 16 x 4 = 64 4 cube = 64
This can be broken into cube root( 64 * 1000) = cube root(64) * cube root(1000) which is 4 * 10 = 40
The answer is 64. The cube-root of 512 is 8, 8 squared is 64.
The cube root of 64 is 4
4