The cubic root of 10 is an irrational number, as 10 is not a perfect cube. The only rational cubic roots are those of perfect cubes. These numbers include:1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.
27/125 is in its simplest form.
27/125 ============Is in lowest terms.
No, it cannot.
Four of them: 1, 8, 27 & 64. Including negative numbers which are all less than 125, there are infinitely many as they also include: -1, -8, -27, -64, -125, -216, ...
The cubic root of 10 is an irrational number, as 10 is not a perfect cube. The only rational cubic roots are those of perfect cubes. These numbers include:1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.
the cube root of 125 is 5, the cube root of 64 is 4, the cube root of 27 is 3, the cube root of 8 is 2, and the cube root of 1 is 1.
27/125 is in its simplest form.
27/125 ============Is in lowest terms.
any number that doesn't have a cube root eg (33) 27 is a cubic number cube root is 3
The only real root is 3. But there are also two complex roots.
1, 8, 27, 64 and 125.
3The cubed root of 27 is 33This is because 3x3x3 =3x3 = 9.9x3 = 27.So your answer is 3
Expressed as a decimal, 4 27/125 is equal to 4.216.
No, it cannot.
27X^3-8 = 0 27X^3 = 8 X^3 = 8/27 X = cubic root of 8/cubic root of 27 = 2/3
27X^3 - 64 = 0 add 64 to each side 27X^3 = 64 divide each side by 27 X^3 = 64/27 take cubic root of each side X = cubic root(64/27) easy cubic root X = 4/3 check 27(4/3)^3 - 64 = 0 27(2.37037037) - 64 = 0 64 - 64 = 0 checks