It can be growth or decay - it depends on whether n is positive (growth) or negative (decay).
If we have y=a(b)^t as the equation then take b from this equation case !: If b <1 then b=1-r r=1-b this r is the decay factor case 2:If b >1 then b=1+r r=b-1 this is the growth factor
Any number below negative one.
The decay of plutonium-240 follows exponential decay kinetics, where the amount remaining is given by the equation: N(t) = N0 * e^(-λt), where N(t) is the amount remaining at time t, N0 is the initial amount, λ is the decay constant, and e is the base of the natural logarithm. The decay constant for plutonium-240 is 0.0106 years^-1. By rearranging the equation to solve for time (t) when N(t) = 9 grams and N0 = 27 grams, you can calculate the time it will take for 27 grams of plutonium-240 to decay to 9 grams. The calculated time will be approximately 20.5 years.
No, the equation y = 102x is not exponential. An exponential function is of the form y = a * b^x, where a and b are constants. In this case, the equation y = 102x is a linear function, as it represents a straight line with a slope of 102 and no exponential growth or decay.
The decay equation you provided is incomplete. Please provide the complete decay equation for further clarification.
The equation for the alpha decay of 226Ra: 88226Ra --> 86222Rn + 24He The alpha particle is represented as a helium (He) nucleus.
The decay equation is:Co-60----------------------Ni-60 + e-
Natural chromium is stable and does not decay/
The equation for the beta decay of 14C: 614C --> 714N + -10e where the e is an electron.
Lead-210 decays by alpha or beta decay. The equation for the alpha decay of 210Pb is: 82210Pb --> 80206Hg + 24He representing the alpha particle as a helium nucleus. The equation for the beta decay of 210Pb is: 82210Pb --> 83210Bi + -10e where the -10e is an electron.
The nuclear decay equation for Po-208 is: Po-208 → Pb-204 + He-4
All nuclear decay is spontaneous.
The nuclear equation for the alpha decay of 242Pu is: ^24294Pu -> ^23892U + ^4He2 This equation shows that the nucleus of 242Pu decays into a nucleus of 238U and an alpha particle, which is a helium-4 nucleus.
The equation for the beta decay of 17F: 917F --> 817O+ 10e + ve where the 10e is a positive beta particle or positron.
The equation for the beta decay of 97Zr is: 4097Zr --> 4197Nb + -10e representing the beta particle as -10e.
Pb-212