Use the formula for the derivative of a power. The square root of (x-5) is the same as (x-5)1/2.
7/2 t^5/2^
The square root of fraction 20 over 25: = √20 ...√25 = √4(5) ......5 = 2√5 .....5 or 2 square root of 5 over 5
I think it is the square root of 5.
5 times the square root of two over 3 times the square root of two equals 5/3
Use the formula for the derivative of a power. The square root of (x-5) is the same as (x-5)1/2.
b over the square root of 5 The square root of 5b squared is 5b, and the simplified form of the square root of 125 is 5 root 5. The 5s then cancel out leaving b over the square root of 5.
The square root needs to be removed from the bottom. To do this multiply the numberater and denominator by the square root of 5. 125xsquare root of five over 5 25square root of 5 is the simplest answer.
7/2 t^5/2^
The square root of fraction 20 over 25: = √20 ...√25 = √4(5) ......5 = 2√5 .....5 or 2 square root of 5 over 5
I think it is the square root of 5.
5 times the square root of two over 3 times the square root of two equals 5/3
y=(8x).5 + (4x).5 = (2+2sqrt(2))x.5 y'=(1 + sqrt(2))/sqrt(x)
Square root of 40 approximately = 6.324555325 / square root of 40 = 0.790569415
5
Derivative with respect to 'x' of (5x)1/2 = (1/2) (5x)-1/2 (5) = 2.5/sqrt(5x)
You can get a decimal approximation with a calculator, with Excel, etc. But if you want to keep it as a square root, the "standard form" is considered to be one that has no square roots in the denominator. In this case, to get rid of the square root in the denominator, you multiply both numerator and denominator by the square root of 5, with the following result: 3 / root(5) = 3 root(5) / root(5) x root(5) = 3 root(5) / 5 That is, three times the square root of 5, divided by 5.