Yes, the derivative of xi with respect to x equals i. Is that what you were trying to ask?
The derivative of 10x is 10. This is irrespective of the value of x.
No, it equals 9, but XI equals 11.
XI= 11 because X equals 10 and I equals 1. So take X+I (10+1) and get XI (11)
V plus VI Equals XI OR V Plus IV Equals IX
The "double prime", or second derivative of y = 5x, equals zero. The first derivative is 5, a constant. Since the derivative of any constant is zero, the derivative of 5 is zero.
The derivative of 10x is 10. This is irrespective of the value of x.
No, it equals 9, but XI equals 11.
x = 10x, so derivative = 10
XI= 11 because X equals 10 and I equals 1. So take X+I (10+1) and get XI (11)
V plus VI Equals XI OR V Plus IV Equals IX
The derivative of cos(x) equals -sin(x); therefore, the anti-derivative of -sin(x) equals cos(x).
Find the derivative of Y and then divide that by the derivative of A
The "double prime", or second derivative of y = 5x, equals zero. The first derivative is 5, a constant. Since the derivative of any constant is zero, the derivative of 5 is zero.
- the derivative with respect to x is 40y - The derivative with respect to Y is 40xSo, since both x and y equal 2, both derivatives yield 40*2 = 80
Following the correct order of operations: derivative of x^2 + 6/2 = derivative of x^2 +3, which equals 2x
(xlnx)' = lnx + 1
Because the derivative of e^x is e^x (the original function back again). This is the only function that has this behavior.