The derivative of 10x is 10. This is irrespective of the value of x.
No, it equals 9, but XI equals 11.
XI= 11 because X equals 10 and I equals 1. So take X+I (10+1) and get XI (11)
V plus VI Equals XI OR V Plus IV Equals IX
The "double prime", or second derivative of y = 5x, equals zero. The first derivative is 5, a constant. Since the derivative of any constant is zero, the derivative of 5 is zero.
The derivative of 10x is 10. This is irrespective of the value of x.
No, it equals 9, but XI equals 11.
x = 10x, so derivative = 10
XI= 11 because X equals 10 and I equals 1. So take X+I (10+1) and get XI (11)
V plus VI Equals XI OR V Plus IV Equals IX
The derivative of cos(x) equals -sin(x); therefore, the anti-derivative of -sin(x) equals cos(x).
Find the derivative of Y and then divide that by the derivative of A
The "double prime", or second derivative of y = 5x, equals zero. The first derivative is 5, a constant. Since the derivative of any constant is zero, the derivative of 5 is zero.
- the derivative with respect to x is 40y - The derivative with respect to Y is 40xSo, since both x and y equal 2, both derivatives yield 40*2 = 80
Following the correct order of operations: derivative of x^2 + 6/2 = derivative of x^2 +3, which equals 2x
(xlnx)' = lnx + 1
Because the derivative of e^x is e^x (the original function back again). This is the only function that has this behavior.