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Let its sides be x and y:-

If: 2(x+y) = 24.5 then y = 12.25-x

If: xy = 36.75 then x(12.25-x) = 36.75 => 12.25x -x^2 -36.75 = 0

Solving the above quadratic equation: x = 7 or x = 5.25

By substitution: x = 7 and y = 5.25

Using Pythagoras' theorem diagonal length works out as 8.75 cm

Q: What is the diagonal length of a rectangle when its perimeter is 24.5 cm and has an area of 36.75 square cm?

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Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]

It works out as: 35 cm or 350 mm

The diagonal works out as length of 33.3 cm or 333 mm To solve this you need to apply the equations for the area of a rectangle (a x b) and the perimeter of a rectangle (2a + 2b) as well as the Pythagorean Theorem (a^2 + b^2 = c^2).

-- Multiply the rectangle's length by itself. ('square' the length) -- Multiply the rectangle's width by itself. ('square' the width) -- Add the two results. -- Find the square root of the sum. It is the length of the diagonal.

To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).

Related questions

Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]

It works out as: 35 cm or 350 mm

The perimeter of this square is 56.569 meters.

The diagonal works out as length of 33.3 cm or 333 mm To solve this you need to apply the equations for the area of a rectangle (a x b) and the perimeter of a rectangle (2a + 2b) as well as the Pythagorean Theorem (a^2 + b^2 = c^2).

-- Multiply the rectangle's length by itself. ('square' the length) -- Multiply the rectangle's width by itself. ('square' the width) -- Add the two results. -- Find the square root of the sum. It is the length of the diagonal.

The perimeter of a square with a diagonal length of 24 square root 2 millimeters (33.94 mm) is: 96 mm

To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).

The perimeter of any rectangle is [ 2 x (length + width) ]. Since the length and width of a square are equal, the perimeter of a square is also [ 2 x (side + side) ] = (4 x side).

~26.16 units.

12.73 feet

If d is the diagonal and h is the height Let, l=length of rectangle we have By pythagrous theorem d square= l square + h square therefore l square= d square - h square

perimeter is the measure around the figure; area is the measure within the figure formula: perimeter: length+length+width+width=perimeter (for square or rectangle) area: length times width= area ( for square or rectangle)