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What is the diagonal length of a rectangle when its perimeter is 24.5 cm and has an area of 36.75 square cm?
Let its sides be x and y:-
If: 2(x+y) = 24.5 then y = 12.25-x
If: xy = 36.75 then x(12.25-x) = 36.75 => 12.25x -x^2 -36.75 = 0
Solving the above quadratic equation: x = 7 or x = 5.25
By substitution: x = 7 and y = 5.25
Using Pythagoras' theorem diagonal length works out as 8.75 cm
What else can I help you with?
How do you find diagonal of rectangle when perimeter and width are known?
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
What is the length of the diagonal of a rectangle with an area of 588 square cm and a perimeter of 980 mm?
It works out as: 35 cm or 350 mm
What is the diagonal length of a rectangle with an area of 532.2672 square cm and a perimeter of 932.4 mm?
The diagonal works out as length of 33.3 cm or 333 mm To solve this you need to apply the equations for the area of a rectangle (a x b) and the perimeter of a rectangle (2a + 2b) as well as the Pythagorean Theorem (a^2 + b^2 = c^2).
What are the steps taken to get the diagonal measurement of a rectangle?
-- Multiply the rectangle's length by itself. ('square' the length) -- Multiply the rectangle's width by itself. ('square' the width) -- Add the two results. -- Find the square root of the sum. It is the length of the diagonal.
How do you count the number of squares crossed by the diagonal in a rectangle?
To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).
How do you find diagonal of rectangle when perimeter and width are known?
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
What is the length of the diagonal of a rectangle with an area of 588 square cm and a perimeter of 980 mm?
It works out as: 35 cm or 350 mm
What is the perimeter of a square that has a diagonal of length 20 meters?
The perimeter of this square is 56.569 meters.
What is the diagonal length of a rectangle with an area of 532.2672 square cm and a perimeter of 932.4 mm?
The diagonal works out as length of 33.3 cm or 333 mm To solve this you need to apply the equations for the area of a rectangle (a x b) and the perimeter of a rectangle (2a + 2b) as well as the Pythagorean Theorem (a^2 + b^2 = c^2).
What are the steps taken to get the diagonal measurement of a rectangle?
-- Multiply the rectangle's length by itself. ('square' the length) -- Multiply the rectangle's width by itself. ('square' the width) -- Add the two results. -- Find the square root of the sum. It is the length of the diagonal.
The length of a diagonal of a square is 24square root 2 millimeters find perimeter of the square?
The perimeter of a square with a diagonal length of 24 square root 2 millimeters (33.94 mm) is: 96 mm
How do you count the number of squares crossed by the diagonal in a rectangle?
To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).
What is the formula for the perimeter of a square and rectangle?
The perimeter of any rectangle is [ 2 x (length + width) ]. Since the length and width of a square are equal, the perimeter of a square is also [ 2 x (side + side) ] = (4 x side).
What is the length of a diagonal of a square with perimeter equals 74?
~26.16 units.
Square has a perimeter of 36 ft determine the length of diagonal square?
12.73 feet
What is the length of a rectangle if the diagonal and height are given?
If d is the diagonal and h is the height Let, l=length of rectangle we have By pythagrous theorem d square= l square + h square therefore l square= d square - h square
What is the difference between perimeter and area of polygon?
perimeter is the measure around the figure; area is the measure within the figure formula: perimeter: length+length+width+width=perimeter (for square or rectangle) area: length times width= area ( for square or rectangle)
