7.0711 (rounded)
The lengths of a square's sides if its area is 5 is: 2.236
The side length of the square is about 3.54 units using Pythagoras' theorem for a right angle triangle
The diagonal of a 5 foot square is about 7.07 feet.
Since all sides of the square are the same length, if the length is 5, the width is five. Therefore area= length x width = 5 x 5 = 25. The answer is 25 square feet.
7.0711 (rounded)
The length of the diagonal of a square with sides 5 is 5√2. This is because of the properties of a 45-45-90 triangle.
The diagonal length = 7.07 inches.
The diagonal of a rectangle is the third and longest side of a triangle with sides the same as those of the rectangle, so its length is the square root of the sum of the squares of the lengths of the sides of the triangle, (Pythoagoras' Theorem) which are also the sides of the rectangle. If the rectangle is 3 inches by 4 inches, then the diagonal is the square root of 3 squared (= 9) and 4 squared (= 16) so the diagonal is the square root of 16 + 9 = 25, giving it the length of 5 inches.
diagonal is 13 inch length of the rectangle of 12 and 5 inches sides
Using the quick method, it is 5√2
To find the side length of a square with a diagonal of 5, we can use the Pythagorean theorem. The diagonal of a square divides it into two 45-45-90 right triangles. Let x be the side length of the square. Using the Pythagorean theorem, we have x^2 + x^2 = 5^2. Simplifying, we get 2x^2 = 25. Solving for x, we find x = √(25/2) = √12.5 = 3.54 (rounded to two decimal places). Therefore, the side length of the square is approximately 3.54 units.
~7.1 cm
The lengths of a square's sides if its area is 5 is: 2.236
"using Pythagoras, you find the length of either of the two sides. For example, if the diagonal is = 5 Then square it = 25 Then Half it (since both of the other sides of one of the triangles are equal) = 12.5 Then Square Root it = sqrt(12.5) The length of one side is sqrt(12.5) So now you can just square it and the area is 12.5 Hope that makes sense" Actually there are steps here you don't need. Use the equation: A= (d^2)/2 Where d=diagonal length. You don't need to square root it then square it again. That would only make sense if you wanted to find the side length, but in that case all you would have to do is divide the diagonal by the square root of 2, which will also give you the side length, but in a much easier way.
If the circle is inscribed in the square, the side length of the square is the same as the diameter of the circle which is twice its radius: → area_square = (2 × 5 in)² = 10² sq in = 100 sq in If the circle circumscribes the square, the diagonal of the square is the same as the diameter of the circle; Using Pythagoras the length of the side of the square can be calculated: → diagonal = 2 × 5 in = 10 in → side² + side² = diagonal² → 2 × side² = diagonal² → side² = diagonal² / 2 → side = diagonal / √2 → side = 10 in / √2 → area _square = (10 in / √2)² = 100 sq in / 2 = 50 sq in.
By the Pythagorean Theorem, the diagonal is the hypotenuse of the right triangle formed by the diagonal and the two included sides. c2 = a2 + b2 so the diagonal is the square root of the sum of the squares of the rectangle's length and width. Example : for a rectangle 4 x 3, the diagonal is sqrt(32 + 42) = sqrt (25) = 5