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If you are familiar with Pythagoras's theorem you will know that it is 5x5 + 5x5

=> 25 + 25=50

find the square root of fifty and you will have your answer

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Q: What is the diagonal length of square when sides are 5 in length?
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What is the length of a diagonal of a square with sides of length 5?

7.0711 (rounded)


What is the length of a diagnal square with sides of length of 5?

The length of the diagonal of a square with sides 5 is 5√2. This is because of the properties of a 45-45-90 triangle.


What is the length of the diagonal of a square with a side length of 5 in?

The diagonal length = 7.07 inches.


What is the formula to find the diagonal of a rectangle?

The diagonal of a rectangle is the third and longest side of a triangle with sides the same as those of the rectangle, so its length is the square root of the sum of the squares of the lengths of the sides of the triangle, (Pythoagoras' Theorem) which are also the sides of the rectangle. If the rectangle is 3 inches by 4 inches, then the diagonal is the square root of 3 squared (= 9) and 4 squared (= 16) so the diagonal is the square root of 16 + 9 = 25, giving it the length of 5 inches.


What is the diagonal of 12 inches and 5 inches?

diagonal is 13 inch length of the rectangle of 12 and 5 inches sides


What is the diagonal of the square has sides of 5 units?

Using the quick method, it is 5√2


What is the side length of a square with a diagonal of 5?

To find the side length of a square with a diagonal of 5, we can use the Pythagorean theorem. The diagonal of a square divides it into two 45-45-90 right triangles. Let x be the side length of the square. Using the Pythagorean theorem, we have x^2 + x^2 = 5^2. Simplifying, we get 2x^2 = 25. Solving for x, we find x = √(25/2) = √12.5 = 3.54 (rounded to two decimal places). Therefore, the side length of the square is approximately 3.54 units.


What is the length of a diagonal of a square with a 5 centimeter side?

~7.1 cm


What is the length of a square's sides if its area is 5?

The lengths of a square's sides if its area is 5 is: 2.236


How do you calculate area of a square using the length of its diagonal?

"using Pythagoras, you find the length of either of the two sides. For example, if the diagonal is = 5 Then square it = 25 Then Half it (since both of the other sides of one of the triangles are equal) = 12.5 Then Square Root it = sqrt(12.5) The length of one side is sqrt(12.5) So now you can just square it and the area is 12.5 Hope that makes sense" Actually there are steps here you don't need. Use the equation: A= (d^2)/2 Where d=diagonal length. You don't need to square root it then square it again. That would only make sense if you wanted to find the side length, but in that case all you would have to do is divide the diagonal by the square root of 2, which will also give you the side length, but in a much easier way.


What is the area of a square with a circle of a radius of 5 inches?

If the circle is inscribed in the square, the side length of the square is the same as the diameter of the circle which is twice its radius: → area_square = (2 × 5 in)² = 10² sq in = 100 sq in If the circle circumscribes the square, the diagonal of the square is the same as the diameter of the circle; Using Pythagoras the length of the side of the square can be calculated: → diagonal = 2 × 5 in = 10 in → side² + side² = diagonal² → 2 × side² = diagonal² → side² = diagonal² / 2 → side = diagonal / √2 → side = 10 in / √2 → area _square = (10 in / √2)² = 100 sq in / 2 = 50 sq in.


How do you find the diagonal of a rectangle?

By the Pythagorean Theorem, the diagonal is the hypotenuse of the right triangle formed by the diagonal and the two included sides. c2 = a2 + b2 so the diagonal is the square root of the sum of the squares of the rectangle's length and width. Example : for a rectangle 4 x 3, the diagonal is sqrt(32 + 42) = sqrt (25) = 5