12'
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20.75 ft
kinetic_energy = ½mv² = ½ × 45 kg × (10 m/s)² = 2250 Joules.
The width is not needed as the distance travelled is 20 times its circumference (= {pi} x diameter): distance = 20 x {pi} x 56cm ~= 3519cm = 35.19m
u do distance/ time= speed
$470