(12 * 8) - (12 + 8) = 96 - 20 = 76
Sum: 16 Product: 48 Difference: 8 Quotient: 3
Product = 35 Sum = 12
6 and 2 are a number pair with a sum of 8 and a product of 12
The product of 4 and 3 is (4 \times 3 = 12). The sum of 4 and 3 is (4 + 3 = 7). To find how much greater the product is than the sum, we subtract the sum from the product: (12 - 7 = 5). Therefore, the product is 5 greater than the sum.
Two integers that have a sum of -7 and a product of 12 are -3 and -4.
Sum: 16 Product: 48 Difference: 8 Quotient: 3
Sum: 16 Product: 48 Difference: 8 Quotient: 3
80 is.
Product(12, 3) = 12*3 Sum(12, 3) = 12 + 3
To solve this problem, we first calculate the sum of 24 and 7, which is 31. Then, we find the difference between 18 and 6, which is 12. Finally, we multiply these two results together: 31 x 12 = 372. Therefore, the product of the sum of 24 and 7 multiplied by the difference of 18 and 6 is 372.
In mathematics, the product of two numbers is the result of multiplying them together, while the sum of two numbers is the result of adding them together. For example, the product of 3 and 4 is 12 (3 x 4 = 12), while the sum of 3 and 4 is 7 (3 + 4 = 7). The product represents the total when quantities are combined through multiplication, while the sum represents the total when quantities are combined through addition.
12-7 =5
The integers 2 and 10 have a product of 20 and a sum of 12.
Product = 35 Sum = 12
The sum of two numbers between 20-40 is 58. The difference is 12
The sum of 72 and 12 is 84. The product of the two numbers is 864.
62